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3 years ago

Which statement conveys the idea in the most concise and precise manner?

Mathematics

2 answers:

yawa3891 [41]2 years ago

8 0

Answer:

Step-by-step explanation:

THE ANSWER IS A BECAUSE ITS THE MOST TO THE POINT (PRECISE) OPTION STATING WHAT IS NEEDED ONLY.

HOPE IT HELPS YOU !!

solong [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Choice A is directly stating what the couple is doing, without any extra information needed.

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Translation: 6 units down s(-4,1), 7(-3, 5), (0,2 )

tia_tia [17]

(-4,-5) (-3,-1) (0,-4)

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2 years ago

Place the correct tiles in the appropriate order to solve the system of equations using the method of substitution:

BabaBlast [244]

Answer:

Okay Buddy again sigh*

Solve 1 equation for 1 variable. ( Put in y = or x = form)
Substitute this expression into the other equation and solve for the missing variable.
Substitute your answer into the first equation and solve.

Check the solution.

Okay Hope it helps Buddy!

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2 years ago

What is the scientific notation of 8,795,000

fgiga [73]

$8,\underbrace{795,000}_{\leftarrow6}=8.795\cdot10^6$

4 0

3 years ago

Read 2 more answers

Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi

natta225 [31]

Answer:

b. circle; $2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

Step-by-step explanation:

The given conic has equation;

$x^2-5x+y^2=3$

We complete the square to obtain;

$(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}$

This is a circle with center;

$(\frac{5}{2},0)$

This implies that;

$x=\frac{5}{2},y=0$

When the circle is rotated through an angle of $\theta=\frac{\pi}{3}$ ,

The new center is obtained using;

$x'=x\cos(\theta)+y\sin(\theta)$ and $y'=-x\sin(\theta)+y\cos(\theta)$

We plug in the given angle with x and y values to get;

$x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3})$ and $y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})$

This gives us;

$x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}$

The equation of the rotated circle is;

$(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}$

Expand;

$(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}$

Multiply through by 4; to get

$4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37$

Write in general form;

$4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0$

Divide through by 2.

$2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

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3 years ago

Hurry! Someone please help me I only have 5 minutes to do this quiz I don’t need you to show all your work just the answer becau

Doss [256]

Answer:

(x+x)(x+x+x)

Step-by-step explanation:

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2 years ago