-6 and 2/3 is the correct answer.
You take the top box and combine it with the bottom right hand box and remove the right stick on the bottom box to continue combination.
Given that a sample of 32 cowboys gave the following years of longevity:
58 52 68 86 72 66 97 89 84 91 91
92 66 68 87 86 73 61 70 75 72 73
85 84 90 57 77 76 84 93 58 47
The stem and leaf display for the data is given as follows:
4 | 7
5 | 2, 7, 8, 8
6 | 1, 6, 6, 8, 8
7 | 0, 2, 2, 3, 3, 5, 6, 7
8 | 4, 4, 4, 5, 6, 6, 7, 9
9 | 0, 1, 1, 2, 3, 7
Answer:
16%
Step-by-step explanation:
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score = 12.5 minutes
μ is the population mean = 17 minutes
σ is the population standard deviation = 4.5 minutes
z = 12.5 - 17/4.5
z = -1
Probability value from Z-Table:
P(x<12.5) = 0.15866
Converting to percentage
= 0.15866 × 100
= 15.866%
Approximately , the percentage of people living in Flint have a travel time to work that is less than 12.5 minutes is 16%
I tired I don’t know if it’s correct
