6x-3y=3
-2x+6y=14.
First step is multiply the top equation by 2, so you have
12x-6y=6
-2x+6y=14
-6y and +6y cancel each other out, so if you simplify, you have
10x=20, which is then solved by dividing each side by 10, and getting x=2.
Now plug x=2 into one of the equations (I chose the first)
6(2)-3y=3
12-3y=3
-3y=-9, divide each side by -3 and get y=3.
so your point is (2,3)
Answer:
1489.2
Step-by-step explanation:
9*102-5.6*102=
102(9+5.6) =
102(9.0+5.6) =
102(14.6) =
102*14.6=
14.6*(100+2) =
(14.6*100+14.6*2) =
(1460+(14+.6) *2) =
1460+(28+1.2) =
1460+(28.0+1.2) =
1460+29.2=
1460.0+
29.2
=1489.2
Answer:
a m=0
Step-by-step explanation:
5(0)+1 = 0+1 = 1
1<4
hope this helps
Let, the age of Mary = M
Age of John = J = 2M
System of Equation would be: M + J = 52
or M + 2M = 52
3M = 52
M = 52/3
M = 17 1/3 Years
J = 34 2/3 Years
Hope this helps!
well, as I said a while back, Heron's Area formula works for any triangle, so long we have all sides, and in this case we do, since it's not a right-triangle SOH CAH TOA won't work, so let's plug the values in Heron's
![\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a = 12\\ b = 8\\ c = 6\\ s=\frac{12+8+6}{2}\\ \qquad 13 \end{cases} \\\\\\ A=\sqrt{13(13-12)(13-8)(13-6)} \implies A=\sqrt{13(1)(5)(7)} \\\\\\ A=\sqrt{455}\implies {\Large \begin{array}{llll} A\approx 21.33 \end{array}}~cm^2](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctextit%7BHeron%27s%20area%20formula%7D%20%5C%5C%5C%5C%20A%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D%5Cqquad%20%5Cbegin%7Bcases%7D%20s%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%20%3D%2012%5C%5C%20b%20%3D%208%5C%5C%20c%20%3D%206%5C%5C%20s%3D%5Cfrac%7B12%2B8%2B6%7D%7B2%7D%5C%5C%20%5Cqquad%2013%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Csqrt%7B13%2813-12%29%2813-8%29%2813-6%29%7D%20%5Cimplies%20A%3D%5Csqrt%7B13%281%29%285%29%287%29%7D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Csqrt%7B455%7D%5Cimplies%20%7B%5CLarge%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%5Capprox%2021.33%20%5Cend%7Barray%7D%7D~cm%5E2)