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zlopas [31]
2 years ago
10

For every pound a company spends on advertising, it spends £0.45 on its website. Express the amount spent on advertising to the

amount spent on its website as a ratio in its simplest form.
Mathematics
1 answer:
Tamiku [17]2 years ago
6 0

If the company spends 100 pounds on advertising, it would spend 0.45 x 100 = 45 pounds on the website.

So, we can write the ratio spent on advertising to the amount spent on its website as 100:45

If we divide both numbers by a same number, we get an equivalent ratio (simplification)

100:45 = (100:5):(45:5) = 20:9

So, the ratio in its simplest form is 20:9

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Rates for having a manuscript typed at a certain typing service are $5 per page for the first time a page is typed and $3 per pa
Goryan [66]

Answer:

D. $680

Step By Step Explanation:

100 pages are typed. Each page coast $5 to type.

100 x 5 = 500

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3 years ago
Families USA, a monthly magazine that discusses issues related to health and health costs, survey 19 of its subscribers. It foun
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Answer:

a

   $10,151   <  \mu  $11448.12

b

  n =  158

Step-by-step explanation:

From the question we are told that

    The  sample size is  n  =  19

    The  sample mean is  \= x  =$10,800

     The  standard deviation is  \sigma  =$1095  

    The  population mean is  \mu  =$225

     

Given that the confidence level is 99%  the level of significance is mathematically represented as

       \alpha  =  100 -99

      \alpha  = 1%

=>    \alpha =  0.01

Now the critical values of \alpha  = Z_{\frac{\alpha }{2} } is obtained from the normal distribution table as

        Z_{\frac{0.01}{2} } =  2.58

The reason we are obtaining values for \frac{\alpha }{2} is because \alpha is the area under the normal distribution curve for both the left and right tail where the 99% interval did not cover while \frac{\alpha }{2}  is the area under the normal distribution curve for just one tail and we need the  value for one tail in order to calculate the confidence interval

Now the margin of error is obtained as

     MOE  =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

    MOE  =  2.58*  \frac{1095 }{\sqrt{19} }

     MOE  =  648.12

The  99% confidence interval for the population mean yearly premium is mathematically represented as

    \= x -MOE  <  \mu <  \= x +MOE

substituting values

   10800 -648.12  <  \mu <  10800 + 648.12

    10800 -648.12  <  \mu <  10800 + 648.12

   $10,151   <  \mu  $11448.12

The  largest sample needed is mathematically evaluated as

      n =  [\frac{Z_{\frac{\alpha }{2}    } *  \sigma }{\mu} ]

substituting values

       n =  [    \frac{ 2.58  *  1095}{225} ]^2

      n =  158

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1-Yes/For example x=29

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3-No

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