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PIT_PIT [208]
3 years ago
15

our goal is to run a mean of 45 minutes per day for a week. For the first six days, you run 38, 40, 40, 42, 43, and 50 minutes.

How many minutes must you run on the seventh day to reach your goal exactly? 28 minutes 62 minutes 4216 minutes 17 minutes
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
6 0

Answer:

62 minutes.

Step-by-step explanation:

To find the mean, you need to <u>add</u> together all of your values (the minutes) and <u>divide</u> them by the number of values (how many sets of minutes given).

So, choosing to add 62 minutes:

38 + 40 + 40 + 42 + 43 + 50 + 62 = 315

There are 7 sets of minutes in total, so we then divide 315 by 7.

315/7 = 45 minutes

Therefore, running 62 minutes on the seventh day would cause you to run a mean of 45 minutes per day for the week.


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x\100*50=40 ?
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x=100*40\50=2*40=80 percent
So the correct answer is C.
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Solve the given triangles by finding the missing angle and other side lengths.
coldgirl [10]

Answer:

  1. a ≈ 27.65; B = 28°; c ≈ 19.17
  2. a ≈ 163.30; B = 120°; c ≈ 59.77
  3. A = 13°; b ≈ 0.3874; c ≈ 1.3737

Step-by-step explanation:

As long as you're seeking outside help, the use of a suitable tool is appropriate. Many graphing calculators, apps, and web sites are available for solving triangles.

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Here, you're given two angles and a side. The third angle is the difference from 180° of the sum of the other two. For example, in the first problem, ...

  B = 180° -A -C = 28°

The missing sides are found using the law of sines. Since you are given a side, use that as the reference, and its opposite angle as the reference angle. Then you have ...

  side = sin(opposite angle)×<em>((reference side)/sin(reference angle))</em>

Note that the factor in italics remains the same for both remaining sides.

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In the first problem, this becomes ...

  a = sin(112°)·14/sin(28°) ≈ 27.65

  c = sin(40°)·14/sin(28°) ≈ 19.17

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The remaining problems are worked in similar fashion.

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<em>Comment on triangle solutions</em>

These are straightforward because you're given two angles. If you're given two sides and an angle, the solution method varies depending on which angle you're given (opposite the long side, the short side, or the unknown side). In the last case, the law of cosines is involved. In the second case, there are likely two solutions. Once you have two angles, you can proceed as above.

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