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2 years ago

Which of the fractions 13/20, 3/5, 3/4 and 7/10 is greatest

Mathematics

2 answers:

Andrei [34K]2 years ago

8 0

Answer:

3/4

Step-by-step explanation:

Maksim231197 [3]2 years ago

7 0

3/4

We can change all fractions to denominator 20 to easily vary them

13/20=13/20

3/5=12/20

3/4=15/20

7/10=14/20

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love history [14]

The second option square root of 2^5

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2 years ago

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A rectangle's length is seven times its width. The perimeter of the rectangle is one hundred sixty feet.

Arada [10]

Answer:

Area=700 square ft

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3 years ago

Given the inequality below: 3x-y>4 Which is the graph of the solution set?

OLga [1]

Answer:

A shaded region below a dashed line (y <3x-4)

Step-by-step explanation:

For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.

Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.

In this case what we have here is an open region, as the graph below shows.

3x-y>4 =-y>4-3x∴y<3x-4

Setting a value for x

3x-4=0

3x=4

3x/3=4/3

x=4/3 (slope)

(4/3,0)

6 0

3 years ago

Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x

Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = $3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4$

$fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}$

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

$x(x^{2}+x) \neq 0$

If x = 0, the function doesn't exist.

$x^{2}+x \neq0$

$x(x+1) \neq0$

$x+1\neq0$

$x\neq-1$

Therefore, the domain of this function is: -∞ < -1 or x > 0

5 0

2 years ago

The circumference of a circular pond is 654 feet.Whats the diameter at a rate of 6 feet per second?

Alex73 [517]

To find the answer we need to find the raduis

Circumference = 2πr
r= $\frac{Circumference}{2 \pi }$
r= $\frac{654}{2 \pi }$
= 104.08

The diameter is 2r, hence the diameter is 208.16

If the rate to cross is 6ft. per second, time can be found by dividing the raduis by 6

It would take 34.7 seconds

8 0

3 years ago

Which of the fractions 13/20, 3/5, 3/4 and 7/10 is greatest​

Which of the fractions 13/20, 3/5, 3/4 and 7/10 is greatest