It is 9 squares. Todayyyyy
What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
Answer:
D is not a supported statement
Step-by-step explanation:
Let take them one by one:
A: from table: 0.57; in statement: 0.5
0.57 > 0.5 so this is supported
B: from table: 0.2+0.16=0.36; in statement: 1/3=0.33,
0.36>0.33 so this is supported
C: 0.07 is the least, so this is supported
D: the table DOES NOT show number of students, but proportions. So statement '7 students' IS NOT supported
E: from table 0.20 overslept. 0.2 < 1/4=0.25, so this is supported
Answer:
Monthly payment would be $99.01
Total repayment would be $5,940.30
Interest payed would be $940.30
Step-by-step explanation: