Answer:
R= q+c over 5y
Step-by-step explanation: Good luck sweetie!!
Answer: b. 8.56 to 21.44
Step-by-step explanation:
Let
be the mean number of pushups that can be done.
As per given , we have
Sample size : n= 10
Degree of freedom = n-1=9
Sample mean : 
Sample standard deviation : 
Significance level : α=1-0.95=0.05
From t- distribution table ,
Critical two -tailed t-value for α=0.05 and df = 9 is

Confidence interval for
is given by :-


Hence, the 95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.
Answer: It will take it 3 seconds before getting to the chicken
2c -7 >= 9
2c >= 16
c >= 8
5d + 7 <= 32
5d <= 25
d <= 5
normal arthematic except diving over -1 or flipping (taking inverse -1) flips the operator
86921 = 80000 + 6000 + 900 +20 +1