The 2-point form of the equation for a line can be used.
... y = (y₂-y₁)/(x₂-x₁)·(x -x₁) +y₁
Filling in the given information, you have
... y = (4-1)/(4-3)·(x-3) +1 . . . . an equation for the line
... y = 3x -8 . . . . . . . . . . . . . . simplified to slope-intercept form
... 3x -y = 8 . . . . . . . . . . . . . .. rearranged to standard form
1. Let A(a,b) be a point in the coordinate axis. The reflection of A with respect to the x-axis is the point A'(a, -b).
2. So the reflection of C(6, 4) is C'(6, -4)
3. Remark, a picture is always helpful when dealing with reflections.
Answer: Width = 5 inches
Concept:
Here, we need to know the idea of the perimeter.
A perimeter is a path that encompasses/surrounds/outlines a shape.
Perimeter of rectangle = 2 (w + l)
w = width
l = length
If you are still confused, please refer to the attachment below for a graphical explanation.
Solve:
w = w
l = 3w - 2
P = 36 inches
<u>Given formula</u>
P = 2 (w + l)
<u>Substitute the value into the formula</u>
36 = 2 (w + 3w - 2)
<u>Simplify values in the parentheses</u>
36 = 2 (4w -2)
<u>Divide 2 on both sides</u>
36 / 2 = 2 (4w - 2) / 2
18 = 4w - 2
<u>Add 2 on both sides</u>
18 + 2 = 4w - 2 + 2
20 = 4w
<u>Divide 4 on both sides</u>
20 / 4 = 4w / 4
w = 5
Hope this helps!! :)
Please let me know if you have any questions
The flag pole is
or write it as
tall.
Step-by-step Explanation:
Let "p" be the height of the flag pole.
The ratio of the child height to the pole height is the same as the ratios of their respective shadows, so,

Now, Cross multiply :-

→ 
→ 
→ 
This
can be rounded off to
as it ends with 
So, the flag pole is <u>9 metres</u> tall.
Sqrt of 125
10^2 +b^2= 15^2
100 +b^2=225
B^2=125
No perfect square for 125 so leave it in radical form