How do I multiply decimals? Examples for this question please

1 answer:

7 0

It's pretty easy actually. First, it's best to aline them from top to bottom. I'll give 2 examples. 1.2 * 2. Multiply like you usually would: 2*2 is 4 and 1*2 is 2. So now we have 24. Now we count the number of spaces from the right of the numbers to the decimal point. So there's one space from 2 to the decimal point. So now, we put the decimal in the answer after one space before the 4 giving you 2.4

Now I'll give you another doing the same. 1.2 * 2.4. Multiply like you would: 288. Now we do the same thing, count from the last number on both numbers to the decimal point: from 2 to the point and from 4 to the point. There are 2 spaces in total meaning we add the decimal 2 spaces: 2.88

I hope you understand how I explained it. It's a little hard explaining using a keyboard but I hope you were able to understand it :)

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Add 3/ 4 + (−2 1/2).

Marat540 [252]

Exact form-13/4

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hope I helped :)

7 0

3 years ago

In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they spent, on average, $54 per hour

Lesechka [4]

Answer:

$54-1.64\frac{21}{\sqrt{16}}=45.39$

$54 +1.64\frac{21}{\sqrt{16}}=62.61$

So on this case the 90% confidence interval would be given by (45.39;62.61)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=54$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=21$ represent the sample standard deviation

n=16 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$