Answer:
13 sweets
Step-by-step explanation:
Fiona : Angad
2 : 1
26 : X
26/2 = X/1
X = 13
Answer:
the value in the five years is £2,621.44
Step-by-step explanation:
The computation of the value in the five years is given below:
= The value of the second car × (1 - losses percentage)^number of years
= £8,000 × (1 - 0.20)^5
= £8,000 × 0.80^5
= £8,000 × 0.32768
= £2,621.44
Hence, the value in the five years is £2,621.44
We simply applied the above formula so that the correct value could come
And, the same is to be considered
Answer:
all two digit whole number which are divisible by 11 are
22+33+44+55+66+77+88+99=484
Answer: 0.5
Step-by-step explanation: In this problem, we're asked to solve the following equation for <em>p. </em>Let's first switch 14 and 14p around so we have 14p + 14 = 21.
<em />
To solve this equation for <em>p</em>, we must first isolate the term containing <em>p</em> which in this case is 14p.
Since 14 is being added to 14p, we need to subtract 14 from both sides of the equation.
14p + 14 = 21
-14 -14
On the left side of the equation, the positive 14 and negative 14 cancel each other out and we have 14p. On the right side of the equation, we hav 21 - 14 which gives us 7.
Now we have the equation 14p = 7.
Since <em>p</em> is being multiplied by 14, to get <em>p</em> by itself, we divide both sides of the equation by 14.
On the left side of the equation the 14's cancel and we are left with <em>p</em>. On the right side of the equation, 7 divided by 14 is 0.5 which is our answer.
Therefore, p = 0.5 which is the solution for our equation.
Remember, you can always check your solution by substituting a number in for a variable to make sure the equation is true.
Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
