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ad-work [718]
4 years ago
9

Add 3/ 4 + (−2 1/2).

Mathematics
1 answer:
Marat540 [252]4 years ago
7 0
Exact form-13/4

decimal form-3.25

mixed number form- 3 1/4

hope I helped :)
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a 15-foot telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42 degre
scoundrel [369]

Answer:

The length of the wire is 22.42 feet

The distance from the base of the pole to the spot where the wire touches the ground is 16.66 feet

Step-by-step explanation:

* Lets explain the situation in the problem

- The telephone pole , the wire and the ground formed a right triangle

- The wire is the hypotenuse of the triangle

- The height of the telephone pole and the distance from the base of

 the pole to the spot where the wire touches the ground are the legs

 of the triangle

- The angle between the wire and the ground is 42°

- The angle 42° is opposite to the height of the telephone pole

- The height of the telephone pole is 15 feet

* Lets use the trigonometry functions to find the length of the wire

 (hypotenuse) and the distance from the base of the pole to the spot

 where the wire touches the ground

∵ sin Ф = opposite/hypotenuse

∵ Ф = 42° and its opposite side = 15 feet

∴ sin 42 = 15/hypotenuse ⇒ by using cross multiplication

∴ sin 42° (hypotenuse) = 15 ⇒ divide both sides by sin 42

∴ hypotenuse = 15/sin 42° = 22.42 feet

∵ The length of the wire is the hypotenuse

∴ The length of the wire is 22.42 feet

∵ The distance from the base of the pole to the spot where the wire

   touches the ground is the adjacent side to the angle 42°

∵ tan Ф = opposite/adjacent

∴ tan 42° = 15/adjacent ⇒ by using cross multiplication

∴ tan 42° (adjacent) = 15 ⇒ divide both sides by sin 42

∴ adjacent = 15/tan 42° = 16.66 feet

∵ The adjacent side is the distance from the base of the pole to the

  spot where the wire touches the ground

∴ The distance from the base of the pole to the spot where the wire

   touches the ground is 16.66 feet

7 0
4 years ago
Statistics??? Construct a 95% confidence interval for the population mean. Assume the population has a normal distribution. A sa
antiseptic1488 [7]
Given:
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.

At the 95% confidence level, the confidence interval is
( \mu - 1.96\frac{\sigma}{ \sqrt{n} }  ,\, \mu + 1.96\frac{\sigma}{ \sqrt{n} })

1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)

Answer: ($2823.29, $3416.71)

6 0
3 years ago
(High points) please solve both with explanation. I’ll give brainliest.
lawyer [7]

Answer:

36\frac{9}{16}

area: 136 cm

perimeter: 48 cm

Step-by-step explanation:

For the first one just subtract

45\frac{1}{2}=\frac{91}{2}=\frac{364}{8}\\8\frac{7}{8}=\frac{71}{8}\\\frac{364}{8}-\frac{71}{8}=\frac{293}{8}\\\frac{293}{8}=\frac{586}{16}\\\\\frac{586}{16}-\frac{1}{16}=\frac{585}{16}=36\frac{9}{16}

for the second one you just have to break it into smaller, more digestible pieces (work below)

7 0
3 years ago
The table shows the cost of different numbers of yards of the material that Marnie wants to buy. Marine needs 3 yards of the mat
valentinak56 [21]
It would cost $14.04. The equation for this would be y = 4.68x. If you multiply 3 by 4.68, you would get 14.04.
7 0
3 years ago
Read 2 more answers
C. None of the above <br> D.translation
Over [174]

C) None of the above

The transformation is not a reflection because the image is not an exact reflection. It is a little bit tilted.

The transformation is not a rotation because the image is not in the same place as the original.

The transformation is not a translation because the image was altered in some way, by being tilted.

7 0
3 years ago
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