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Find the vertical asymptotes. 2x2 + 7x + 6 y = 3x2 + 10x - 8 * = [ [?], x=

Llana [10]

Answer:

$-\frac{77}{24}$

Step-by-step explanation:

1. rewrite the equation in standard form: $4\cdot \frac{3}{2}\left(y-\left(-\frac{41}{24}\right)\right)=\left(x-\left(-\frac{3}{2}\right)\right)^2$

2. find (h,k), the vertex. the vertex is $\left(h,\:k\right)=\left(-\frac{3}{2},\:-\frac{41}{24}\right)$

3. find the 'focal length' of the parabola - the focal length is the distance between the vertex and the focus. from the vertex we can see that the focal length, p, = 3/2

4. Parabola is symmetric around the y-axis and so the asymptote is a line parallel to the x-axis, a distance p from the $\left(-\frac{3}{2},\:-\frac{41}{24}\right)$ y coordinate which is at $-\frac{41}{24}\right)$ . Set up the equation:

$y=-\frac{41}{24}-p$

5. substitute and solve:

$y=-\frac{41}{24}-\frac{3}{2}$

$y = -\frac{77}{24}$

hope this helps, ask me questions if you still don't understand.

8 0

3 years ago

In 2010, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephon

Zepler [3.9K]

<u>Answer</u>: No, we do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

Step-by-step explanation:

As per given , we have

$H_0: \mu=9.4\\\\H_a:\mu\neq9.4$ , since $H_0$ is two-tailed so , the test is a two tail test.