1.) C(t) = -0.30(t - 12)^2 + 40
for t = 12: C(12) = -0.30(12 - 12)^2 + 40 = -0.30(0)^2 + 40 = 40°C
For t = 24: C(24) = -0.30(24 - 12)^2 + 40 = -0.30(24 - 12)^2 + 40 = -0.30(12)^2 + 40 = -0.30(144) + 40 = -43.2 + 40 = -3.2°C
4.) F(t) = 9/5 C(t) + 32
for C(t) = 40°C: 9/5 (40) + 32 = 72 + 32 = 104°F
for C(t) = -3.2°C: 9/5(-3.2) + 32 = -5.76 + 32 = 26.24°F
5.) F(t) = 9/5 C(t) + 32 = 9/5 (-0.30(t - 12)^2 + 40) + 32 = -0.54(t - 12)^2 + 72 + 32 = -0.54(t - 12)^2 + 104
Answer:
dff
Step-by-step explanation:
saf
ON/MN=NP/NQ
ON/12=15/20
ON=(12*15)/20
ON=9
Answer:
<u><em>Hi there the correct answer will be is B) (-1,5), (1, 3), (3, 1), (5,0)</em></u>
hope it helps to your question!
