Answer:
g(0.9) ≈ -2.6
g(1.1) ≈ 0.6
For 1.1 the estimation is a bit too high and for 0.9 it is too low.
Step-by-step explanation:
For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.
For 0.9, we estimate
g(0.9) ≈ 16* (-0.1) -1 = -2.6
g(1.1) ≈ 16* 0.1 -1 = 0.6
We have:
3x + 4y = 12
The first thing we should do in this case is clear and.
We have then:
4y = -3x + 12
y = (- 3x + 12) / (4)
Rewriting:
y = (- 3/4) x + 3
We evaluate now for x = 4
y = (- 3/4) (4) + 3
y = -3 + 3
y = 0
The ordered pair is:
(x, y) = (4, 0)
Answer:
y = (- 3/4) x + 3
(x, y) = (4, 0)
Answer:
x1 = 2, y1 = 0
x2 = 2, y2 = 6
Step-by-step explanation:
Each pair of coordinates is (x, y). The first pair is (x1, y1). The second pair is (x2, y2). This means you have ...
x1 = 2, y1 = 0
x2 = 2, y2 = 6
_____
<em>Additional comment</em>
The slope of the line through these points is ...
m = (y2 -y1)/(x2 -x1) = (6 -0)/(2 -2) = 6/0 = undefined
The line through these points is a vertical line with equation x = 2.
Answer= .2 probability
Explanation: Since there is a total of 10 marbles, and 2 are red, you would divide the red marbles (2) out of the total marbles (10) which would get u .2. Since it’s asking for probability, we would keep .2 a decimal.
A. To be able to have the 2 sides ( the 2 triangles) line up correctly, Net A would be the correct one.
B. AB = 3
BC = 5
CD = 9.4
C. Surface area:
9.4 x 5 = 47
9.4 x 3 = 28.2
9.4 x 4 = 37.6
3 x 4 = 12
Total: 47 + 28.2 + 37.6 + 12 = 124.8 sq. in.
