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oksano4ka [1.4K]
3 years ago
13

Javon plays on the Bunker Hill basketball team and Coach Jones sets a goal for him to average a minimum of 18 points per game in

his first six games. If he scores 20, 17, 14, 18, and 19 in his first five games, what must he score in his sixth game to average at least 18 points per game (express your answer as an inequality)?
Mathematics
1 answer:
Misha Larkins [42]3 years ago
4 0

If he does average exactly 18 points per game in the first 6 games, then his TOTAL points in those 6 games will be (6 x 18) = 108 points.

In his first 5 games, he has (20 + 17 + 14 + 18 + 19) = 88 points so far.

In order to total 108 for 6 games, he has to score (108 - 88) = 20 points in the 6th game. If he scores more than that, then his average for the 6 games will be more than 18 points per game.

In order to meet the goal that Coach Jones has set for him, Javon must score 20 points or more in the next game. S ≥ 20 .

This might scare Javon ... he has to equal or beat his best performance of the last 5 games.

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The horizontal axis is calibrated starting from 0 with increment of 1 and the vertical axis is calibrated starting from 0 with the increment of 5.

From the given function rule, when c = 0 (i.e. when the truck is carrying no car) the weight of the truck is given by w = 37,000 + 4,200(0) = 37,000

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3 0
3 years ago
X(x-4)=12 solve for x​
Ivenika [448]

Answer:

x=6 and x=-2

Step-by-step explanation:

so

x(x-4)=12

first distribute

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and the u get

x=6 and x=-2

hope this helped

5 0
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Reptile [31]

Check the picture below.

since the circle is centered at the (0,0) origin, and a point on it is at (0, -9), its radius is simple the distance between those two, or r = 9.

if the second point is also on the circle, it must also be 9 units away from the origin.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{\sqrt{17}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(8-0)^2+(\sqrt{17}-0)^2}\implies d=\sqrt{8^2+(\sqrt{17})^2} \\\\\\ d=\sqrt{64+17}\implies d=\sqrt{81}\implies d=9~~\textit{\Large \checkmark}

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