68.76 rounded to the nearest whole number

Which phrases can be represented by the algebraic expression x + 14? Select three options.

Snezhnost [94]

Answer:

a number plus 14

fourteen more than a number

a number increased by 14

Step-by-step explanation:

The phrases which can be represented by the algebraic expression x + 14 are

Let x = the unknown number

a number plus 14

= x + 14

fourteen more than a number

= x + 14

a number increased by 14

x + 14

4 0

2 years ago

Read 2 more answers

What is 7/81 + 7/9 as a proper fraction

Lorico [155]

70/81 is 7/81+7/9 as a proper fraction

3 0

3 years ago

6th grade math help me pleaseee

creativ13 [48]

Answer:

B and D

Step-by-step explanation:

First off, we can rotate it. When rotating, I found that the x and y values switch places in a way.

We would need to rotate it 90 degrees counterclockwise about the origin in order to get it in the same position as triangle BDE. This makes statement B correct.

In order to make triangle ABC smaller, the dilation would have to be smaller than one. Counting the right side's length, ABC has 6 squares and BDE has 3.

This would mean 6 * 1/2 = 3, meaning statement D is true.

6 0

3 years ago

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How do you do this question? 24 is what percent of 32?

Eddi Din [679]

24 = x% * 32

24= x/100 * 32

Multiply 100 on both sides.

2400 = x * 32

32x = 2400

Divide 32 on both sides.

x = 2400/32

x = 75

75 percent<span> of 32 is 24</span>

6 0

2 years ago

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The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough

liberstina [14]

Answer:

a) $t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

$\bar X=1175$ represent the sample mean for the cubic feets of households

$\sigma=250$ represent the population standard deviation

$n=100$ sample size

$\mu_o =1425$ represent the value to verify

$\alpha=0.025$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:

Null hypothesis: $\mu \geq 1425$

Alternative hypothesis: $\mu < 1425$

Since we don't know the deviation the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0

3 years ago