Ask question

Ask question

All categories

3 years ago

10

Mitchell jogged 2.2 miles on Friday. He jogged 0.7 miles less on Saturday than on Friday. What was the total distance he jogged

on the two days?

2 answers:

Nookie1986 [14]3 years ago

7 0

You jogged 3.7 total miles! 2.2 - 0/7 = 1.5 + 2.2 = 3.7! Hope I helped!

Nutka1998 [239]3 years ago

7 0

Friday = 2.2 miles Saturday = 2.2 - 0.7 = 1.5 miles

2.2 + 1.5 = 3.7

He jogged 3.7 miles on the two days.

You might be interested in

An ice cream shop sells large cones for $2.50 and small cones for $1.50. Jack has enough money to buy 21 large cones. How many s

Strike441 [17]

Answer:

35 cones

Step-by-step explanation:

21 x $2.50

=52.5

52.5/$1.50

= 35 small cones he can buy

6 0

3 years ago

Read 2 more answers

2^2 x 3 x 5^2 is the prime factorization of

sineoko [7]

Answer:

300

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Here is a balanced hanger diagram in which a circle has a mass of 3 grams and a square has a mass of 2 grams.

iris [78.8K]

Answer:

3

(

3

)

+

6

(

2

)

+

2

=

2

(

3

)

+

3

(

2

)

+

5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

{{Geomotry}} <br> please I need help! My math grade depends on it! ;w;

lozanna [386]

This basically means that you have to multiply the x and y values by 3. So 2 time 3 is 6. And -7 times 3 is -21. So the new coordinations are (6, -21)

Hope this helped and pls mark as brainliest!

~ Luna

3 0

4 years ago

Barack walks 2 kilometers south and then x kilometers east. He ends 5 kilometers away from his starting position. Find x

amid [387]

Answer:

4.6 km

Step-by-step explanation:

-This is a Pythagorean Theorem problem where the distances walked are effectively the base and height of the imaginary right triangle thereof.

#Apply Pythagorean theorem to solve:

$b^2+h^2=H^2\\\\2^2+x^2=5^2\\\\x^2=5^2-2^2=21\\\\x=\sqrt{21}\\\\x=4.58\ km$

$\approx 4.6\ km$

Hence, the distance x is 4.6 km

7 0

3 years ago