Question

AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Answer 1

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

$Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds$

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

$\frac{200}{60} = \frac{10}{3} \approx 3.33$   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

$\frac{200}{65} = \frac{40}{13} \approx 3.08$   loops per minute

then the period is:

$\frac{13}{40} =0.325\,\,\,minutes$

Therefore runner B has the smaller period