Answer:
<u>Given function</u>
#15 Find the inverse of h(x)
<u>Substitute x with y and h(x) with x and solve for y:</u>
- x = 2y - 1
- 2y = x + 1
- y = 1/2x + 1/2
<u>The inverse is:</u>
#16 The graph with both lines is attached.
The x- and y-intercepts of both functions have reversed values.
#17 Table of the inverse function will contain same numbers with swapped domain and range.
<u>Initial look is like this:</u>
- <u>x | -3 | -2 | -1 | 0 | 1 | 2 | 3</u>
- h⁻¹(x) | -1 | | 0 | | 1 | | 2
<u>The rest of the table is filled in by finding the values:</u>
- <u>x | -3 | -2 | -1 | 0 | 1 | 2 | 3</u>
- h⁻¹(x) | -1 | -0.5 | 0 | 0.5 | 1 | 1.5 | 2
Answer:
yea
Step-by-step explanation:
Answer: See explanation
Step-by-step explanation:
Your question isn't really clear. Let me help you rephrase it and solve.
Let's say Cesar is creating a schedule to practice his instrument for band. He needs to practice for a total of 10 hours in a week. On Monday he practice for 1 1/2 hours, on Tuesday he practiced for 2 1/4 hours, and on Wednesday he practiced for 1 1/2 hours.
The total hours that Cesar has used in practicing will be:
= 1 1/2 + 2 1/4 + 1 1/2
= 5 1/4
To get the number of hours that Cesar need to practice during the rest of the week in order to have his 10 total hours, we subtract 5 1/4 hours from 10 hours. This will be:
= 10 - 5 1/4
= 4 3/4 hours.
Cesar needs to practice for 4 3/4 hours more.
Answer:
Step-by-step explanation:
−4(−4u3−2+v2)
=(−4)(−4u3+−2+v2)
=(−4)(−4u3)+(−4)(−2)+(−4)(v2)
=16u3+8−4v2
=16u3−4v2+8
Answer:
Option A.)−4
Step-by-step explanation:
we have
4x+5y=-12 -----> equation A
-2x+3y=-16 -----> equation B
Solve the system of equations by elimination
Multiply the equation B by 2
2*(-2x+3y)=-16*2
-4x+6y=-32 -----> equation C
Adds equation A and equation C
4x+5y=-12
-4x+6y=-32
-----------------
5y+6y=-12-32
11y=-44
y=-4
