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2 years ago

Find the distance from the point to the given plane. (1, −7, 8), 3x + 2y + 6z = 5

1 answer:

5 0

3x + 2y + 6z = 5??
then
distance = |3(1) + 2(-2) + 6(4) - 5| / √(3^2 + 2^2 + 6^2)
the plane is ax + by + cz - d = 0 while the point is (x1, y1, z1)

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Semmy [17]

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2 years ago

"Tegan is trying to decide if a coin is fair. She flips it 100 times and gets 63 heads. Please explain why it might make sense t

Naily [24]

Answer:

Should be a 50/50 chance

Step-by-step explanation:

When you flip a coin there are 2 possible chances, heads or tails. That means that out of 100 there should a 50/50 chance to get both. By Tegan getting 63 heads it show how the mentailty that it should be a perfect 50/50 chnace to get heads is not real and therefore not fair.

(but in real life this is what happens. Its not fair).

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2 years ago

What is 4/9 of 6/7 ton

luda_lava [24]

Answer

14/27

Step-by-step explanation:

4/9 / 7/6 = 14/27

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3 years ago

Read 2 more answers

Please help with this math question!

alisha [4.7K]

$Use\ a^\frac{n}{m}=\sqrt[m]{a^n}.\\\\4^\frac{3}{5}=\boxed{\sqrt[5]{4^3}}=\boxed{\sqrt[5]{64}}$

5 0

2 years ago

1) 3r² – 2r=-9<br> Quadratic formula

Nonamiya [84]

Answer:

Solving the equation $3r^2-2r=-9$ using quadratic formula we get: $\mathbf{ r=\frac{1+\sqrt{26}\:i}{3}\:or\: r=\frac{1-\sqrt{26}\:i}{3}}$

Step-by-step explanation:

We need to solve the equation $3r^2-2r=-9$ using quadratic formula.

The quadratic formula is: $r=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

For the given equation: $3r^2-2r=-9$

We can write it as: $3r^2-2r+9=0$

We have a = 3, b= -2 and c=9

Putting values in quadratic formula and finding value of r

$r=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\r=\frac{-(-2)\pm\sqrt{(-2)^2-4(3)(9)}}{2(3)}\\r=\frac{2\pm\sqrt{4-108}}{6}\\r=\frac{2\pm\sqrt{-104}}{6}\\We\:know\:that: \sqrt{-1}=i\\ r=\frac{2\pm\sqrt{26} \:i}{6}\\ r=\frac{2+2\sqrt{26}\:i}{6}\:or\: r=\frac{2-2\sqrt{26}\:i}{6}\\ r=\frac{2(1+\sqrt{26}\:i)}{6}\:or\: r=\frac{2(1-\sqrt{26}\:i)}{6}\\ r=\frac{1+\sqrt{26}\:i}{3}\:or\: r=\frac{1-\sqrt{26}\:i}{3}$

So, solving the equation $3r^2-2r=-9$ using quadratic formula we get: $\mathbf{ r=\frac{1+\sqrt{26}\:i}{3}\:or\: r=\frac{1-\sqrt{26}\:i}{3}}$

3 0

2 years ago