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2 years ago

14

If Zoe has 9 apples, and each apple were 9 grams of sugar. How many grams of sugar does Zoe ate if see eats 9 apples each day th

is week.

1 answer:

lisov135 [29]2 years ago

7 0

Answer: 567

Step-by-step explanation: 9*9=81 then you take 81 and times it by however many days there is in the week (aka 7) 81*7=567

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2 years ago

How are ∠1 and ∠2 related

andreyandreev [35.5K]

Answer:

D. They are adjacent

Step-by-step explanation:

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2 years ago

In ΔIJK, j = 540 inches, ∠I=54° and ∠J=69°. Find the area of ΔIJK, to the nearest square inch.

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2 years ago

If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?

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2 years ago

Scientists have discovered a vaccine for a debilitating disease. This year there were 570,000 reported new cases of the disease

Ket [755]

Answer: There are approximately 853827 new cases in 6 years.

Step-by-step explanation:

Since we have given that

Initial population = 570000

Rate at which population decreases is given by

$\frac{2}{3}$

Now,

First year =570000

Second year is given by

$570000\times (\frac{1}{3})$

Third year is given by

$570000(\frac{1}{3})^2$

so, there is common ratio ,

it becomes geometric progression, as there is exponential decline.

so,

$570000,570000\times \frac{1}{3},570000\times( \frac{1}{3})^2,......,570000\times (\frac{1}{3})^6$

a=570000

common ratio is given by

$r=\frac{a_2}{a_1}=\frac{1}{3}$

number of terms = 6

Sum of terms will be given by

$S_n=\frac{a(1-r^n)}{(1-r)}$

We'll put this value in this formula,

$S_6=\frac{570000(1-(\frac{1}{3})^6}{(1-\frac{1}{3})}\\\\=853827.16$

So, there are approximately 853827 new cases in 6 years.

6 0

2 years ago