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aleksklad [387]
4 years ago
11

Which category of two-dimensional shapes apply to all three of these shapes?

Mathematics
2 answers:
stira [4]4 years ago
5 0
Trapezoid would be your answer your welcome! :)
aliina [53]4 years ago
3 0
D. The answer is a rectangle.

The rectangle is the main source of all these shapes.


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Use the scatter plot of car resale values to answer the following question.
Nataly_w [17]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Do I have to solve this before graphing it and if so how do I go about it?
defon

Given the System of Equations:

\begin{cases}y=4x-1 \\  \\ y=x-4\end{cases}

The exercise asks for solving it graphically. Then, in this case, you need to graph both lines in order to determine the solution of the system.

In order to graph it, you can find the x-intercepts and the y-intercepts:

1. It is important to remember the Slope-Intercept Form of the equation of a line:

y=mx+b

Where "m" is the slope of the line and "b" is the intercept.

In this case, you can identify that the y-intercept of the first line is:

b_1=-1

And the y-intercept of the second line is:

b=-4

2. By definition, the value of "y" is zero when the line intersects the x-axis.

Then, you need to substitute the following value of "y" into each equation and then solve for "x", in order to find the x-intercept of each line:

y=0

- For the first line, you get:

\begin{gathered} y=4x-1 \\ 0=4x-1 \\ 1=4x \\  \\ \frac{1}{4}=x \\  \\ x_1=0.25 \end{gathered}

- For the second line, you get:

\begin{gathered} y=x-4 \\ 0=x-4 \\ 4=x \\ x_2=4 \end{gathered}

3. Now you know that the first line passes through these two points:

(0.25,0);(0,-1)

And the second line passes through these two points:

(4,0);(0,-4)

4. Knowing those points, you can graph the lines:

Notice that the line intersect each other at

5 0
1 year ago
I need help pls thank y
otez555 [7]
What do you need help with
5 0
3 years ago
This is really confusing can someone help?
Dmitriy789 [7]

Answer:

D.780.8

Step-by-step explanation:

multiply 244 and 3.2 and you get D. hope this helps.

4 0
4 years ago
Read 2 more answers
Of all the rectangles with a perimeter of 168 feet, find the dimension of the one with the largest area
dolphi86 [110]
<span>The rectangle with the largest area with a given perimeter will be a square - so the sides will be equal. So we need to find length of side, L, such that 4*L=168. L = 168/4 L=42. So the dimensions of the rectangle that maximizes the area with a perimiter of 168 feet are: 42 feet by 24 feet.</span>
3 0
4 years ago
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