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tangare [24]
2 years ago
5

How to I do an algebra proof if given: m=1/2(a+b) prove: b=2m-a

Mathematics
1 answer:
jolli1 [7]2 years ago
3 0

let's solve for b :

  • m =  \dfrac{1}{2} (a + b)

  • 2m = a + b

  • b = 2m - a

proved....

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Write an equation that is parallel to y=-1/4x+2
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Answer:

y = -1/4 -5

Step-by-step explanation:

Any equation will be parallel to your base equation as long as the y intercept is different. To write a parallel equation, you just have to change the y intercept.

For example, I changed it from 2 to negative 5.

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There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,
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<h2 /><h2>Here we go ~ </h2>

According to given information there are :

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<h3>1. what is the probability that the ball chosen is red ?</h3>

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\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{total \: red \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{25}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{1}{5}

<h3>2. what is the probability that the ball chosen is blue ?</h3>

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{total \: blue \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{25}

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{total \: yellow\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{25}

<h3>4. what is the probability that the ball chosen is green ?</h3>

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{total \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{25}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{2}{5}

<h3>5. what is the probability that the ball chosen is not green ?</h3>

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{total \: non \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{15}{25}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{3}{5}

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<span>                   a⁴(3a² - 2a + 1)

We just have to multiply each term inside the parentheses by  a⁴  .

           a⁴</span><span>(3a²        )  =  3a⁶
 
           a⁴</span><span>(    - 2a    )  =  -2a⁵
 
           a⁴</span><span>(            1)  =  a⁴

Now, just addum up :      3a⁶ - 2a⁵ + a⁴</span>


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