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VladimirAG [237]
3 years ago
12

HELP PLEASE THANKS......

Mathematics
1 answer:
Alexandra [31]3 years ago
6 0
The answer to your question is B
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Enter your answer and show all the steps that you use to solve this problem in the space provided.
rodikova [14]

Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

5 0
2 years ago
Further mathematics: Find the derivative of the function x^2 y + (xy)^3 +3x=0 at (-1 , 3)​
vesna_86 [32]

Answer:

3.

Step-by-step explanation:

Implicit differentiation:

x^2 y + (xy)^3 + 3x = 0

x^2 y + x^3y^3 + 3x = 0

Using the product rule:

2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0

2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0

dy/dx(x^2 + 3y^2x^3) =  (-2xy - 3x^2y^3 - 3)

dy/dx=  (-2xy - 3x^2y^3 - 3) / (x^2 + 3y^2x^3)

At the point (-1, 3).

the derivative =  (6 - 81 - 3)/(1 -27)

= -78/-26

=  3.

8 0
2 years ago
Read 2 more answers
Help how you do this ?
Eddi Din [679]
Ok, so this is a spelling sort of work sheet, you need to say each word aloud and if the A in the word is long, then put it in the long A box, if it's a short sounding A, then put it in the short A box.

Hope this helps >.<
6 0
2 years ago
Read 2 more answers
Help pleaseeeeeeeeeeeeeeeee
jok3333 [9.3K]

Answer:

D(- 1) = 2

Step-by-step explanation:

To evaluate D(- 1), substitute x = - 1 into D(x) , that is

D(- 1) = (- 1)² - 2(- 1) - 1 = 1 + 2 - 1 = 2

6 0
3 years ago
Read 2 more answers
Given that f(x) = x – 2 and g(x) = x2 + 3x – 4, find (f – g)(x).
Svetradugi [14.3K]

Answer:

(f-g)(x)

= -x^2 - 2x + 2

Step-by-step explanation:

(f-g)(x) means

f(x) - g(x)

= x - 2 - (x^2+3x-4)

distribute the subtraction to all three of the last terms.

= x - 2 - x^2 - 3x + 4

combine like terms

= -x^2 - 2x + 2

8 0
2 years ago
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