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Paladinen [302]
4 years ago
5

Draw a Lewis Structure for CCIF3 and indicate how many bonds are present.

Chemistry
1 answer:
harkovskaia [24]4 years ago
4 0

Answer:

c:3

Explanation:

i know

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An electron in a hydrogen atom drops from energy level e3 to e2. what's the frequency of the emitted photon
castortr0y [4]
For this problem we can use 2 equations.
(1) - E = mC²
          E = Energy of photon (J)
          m = Mass of photon (kg) (1.67x10⁻²⁷ kg)
          C = speed of light (3 x 10⁸ m/s)

(2) - E = hf
        E = Energy of photon (J)
        h = plank's constant (6.63 × 10⁻³⁴<span>J s)
        f  = frequency of the photon (Hz)

(1) = (2)
hence, </span>mC² = fh                
                
by rearranging, 
                f =  mC² / h 
                f  =  1.67x10⁻²⁷ kg * (3 x 10⁸ m/s)² / (6.63 × 10⁻³⁴J s)
              f    = 2.27 x 10²³ Hz            
3 0
3 years ago
An unknown compound is treated at 0o C with bromine in the dark (reaction 1). The predominant product of this reaction is treate
miskamm [114]

Answer:

fgfgfgf

Explanation:v

6 0
3 years ago
How are all atoms similar?
attashe74 [19]

Answer:

A. They can not be divided.

Thank you.

BY GERALD GREAT.

5 0
3 years ago
If it takes ashley 3 seconds to run from the battere box to first base at an average speed of 4 meters per second, whar is the d
mrs_skeptik [129]

If it takes Ashley 3 seconds to run from the batters box to first base at a speed of 6 meters per second, the distance she covers in that time is 18 meters!

<em>Hope this helps! (:</em>

6 0
4 years ago
1A. A strontium hydroxide solution is prepared by dissolving 10.45 g of Sr(OH)2 in water to make 41.00 mL of solution. What is t
horrorfan [7]

Answer:

1. 0.00352 M

2. 2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)

3. 0.00534 M

Explanation:

1.

Mass of strontium hydroxide= 10.45 g

Volume of solution = 41.00 ml

Number of moles = mass of Sr(OH)2/molar mass of Sr(OH)2 = 10.45g/121.63 g/mol= 0.0859 moles

Molarity= number of moles × volume = 0.0859 ×41/1000 = 0.00352 M

2.

2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)

3.

Concentration of acid CA= the unknown

Volume of acid VA= 31.5 ml

Concentration of base CB= 0.00352 M

Volume of base VB= 23.9 ml

Number of moles of acid NA= 2

Number of moles of base NB= 1

From;

CAVA/CBVB = NA/NB

CAVANB= CBVBNA

CA= CBVBNA/VANB

CA= 0.00352 × 23.9 ×2/31.5 ×1

CA= 0.00534 M

7 0
3 years ago
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