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Ilia_Sergeevich [38]
3 years ago
15

Help??? question 3 gggggg

Mathematics
2 answers:
dmitriy555 [2]3 years ago
7 0
The answer would be 19
Work:
F(5)= 2(5)+4=14
G(-3)= (-3)^2-4=5
14+5=19
vodka [1.7K]3 years ago
3 0
Your answer is D. You simply plug in the values of each function into the function itself, and then add them together.
f(5)=36, g(-3)=5
36+5=41
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andreev551 [17]

Answer:

Step-by-step explanation:

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3 years ago
I’m having a bit of trouble could someone please help me??
FinnZ [79.3K]

Answer:

1.Conduction

2.the second one

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Step-by-step explanation:

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3 years ago
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A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t
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Full Question

A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.

Determine the spring constant k.

Answer:

Spring Constant = 1000Nm^-1

Step-by-step explanation:

Given

Mass = 10kg

Spring Extension = 9.8cm

Spring Constant K = Force/Extension

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3 0
3 years ago
What is an equation of the line passing between(4, -6) and (12, -8)?*
I am Lyosha [343]

Answer:

y= -1/4x - 5

Step-by-step explanation:

first you need to find the slope.

to do this you can use the equation: change in y/change in x which is also y2 - y1/x2-x1

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-2/8

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since the line's equation is y = mx + b, we still need to find the y-intercept. we can do this by just plugging in one of the points

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3 years ago
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lions [1.4K]

Answer: 0.145

Step-by-step explanation:

Since,

the Probability of the older pump failing P(fail older) = 0.10

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P(not fail older) = 0.9

Also,

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The probability of the pumping system failing = P(not fail older)* P(not fail newer) = 0.9*0.95

P(not fail system)= 0.855

Therefore,

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The probability that the pumping system will fail one day is 0.145

3 0
3 years ago
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