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arlik [135]
3 years ago
10

If sin x = -3/5 and cos x > 0 what is the value of tan x​

Mathematics
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

tan x = opp / adj = -3/4

Step-by-step explanation:

If sin x = -3/5, then we have the following info as a starting point:

opposite side = -3 (implying that the angle is in either QIII or QIV), and

hypotenuse = 5.

Using the Pythagorean Theorem, we find that x² + (-3)² = 5², where x is the length of the adjacent side.  Solving for x², we get x² = 25-9 = 16, so that the adj. side, x, is either +4 or -4.

If cos x > 0, then x must be in either QI or QIV.  

If both conditions are satisfied (sin x = -3/5 and cos x > 0), then the angle x must be in QIV.

Then tan x = opp / adj = -3/4.

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Step-by-step explanation:

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<u>Note that </u>

\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)

<u>You can confirm it: </u>

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<u>Therefore</u>

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