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3 years ago

Please help with this!!!!

Mathematics

2 answers:

sveta [45]3 years ago

8 0

The other angel is also equal to x and the sum of all angels need to be 360:

2x+90+26=360

2x=244

X=122

Anna71 [15]3 years ago

6 0

Answer:

The answer is 112

Step-by-step explanation:

Because seven ate nine :D but seriously 90+26+2x=360 so thats

116+2x=360 and 360-116 is 244 and you divide that by the remaining 2

and that gives you your answer of 112

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The graph of the piecewise function f(x) is shown. 1 f(x)

Tema [17]

Answer:

In a word processing document or on a separate piece of paper, use the guide to construct a two-column proof proving that lines l and m are parallel.

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2 years ago

Julio separates his building blocks he draws a model to show how he separates his blocks . what division sentence does his model

pochemuha

Were is the model????

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2 years ago

Solve the system using elimination 3x+y=27 -3x+4y=-42

padilas [110]

Hello :)

3x+y=27

-3x+4y= -42

+____________

(3x -3x) + (y+4y) = (27-42)

0 + 5y = -15

y = -3

Put "-3" for "y" in the system:

3x + y =27

3x -3=27

3x = 30

x = 10

Answer = x:10 y: -3

Have a nice day :)

8 0

2 years ago

11×11=4 22×22=16 33×33=?

Kay [80]

This is your answer 33 x 33 = 4^3 = 64

7 0

3 years ago

PLEASE HELP 100 POINTS!!!!!!

horrorfan [7]

Answer:

A) See attached for graph.

B) (-3, 0) (0, 0) (18, 0)

C) (-3, 0) ∪ [3, 18)

Step-by-step explanation:

Piecewise functions have multiple pieces of curves/lines where each piece corresponds to its definition over an interval.

Given piecewise function:

$g(x)=\begin{cases}x^3-9x \quad \quad \quad \quad \quad \textsf{if }x < 3\\-\log_4(x-2)+2 \quad \textsf{if }x\geq 3\end{cases}$

Therefore, the function has two definitions:

$g(x)=x^3-9x \quad \textsf{when x is less than 3}$

$g(x)=-\log_4(x-2)+2 \quad \textsf{when x is more than or equal to 3}$

When graphing piecewise functions:

Use an open circle where the value of x is not included in the interval.
Use a closed circle where the value of x is included in the interval.
Use an arrow to show that the function continues indefinitely.

First piece of function

Substitute the endpoint of the interval into the corresponding function:

$\implies g(3)=(3)^3-9(3)=0 \implies (3,0)$

Place an open circle at point (3, 0).

Graph the cubic curve, adding an arrow at the other endpoint to show it continues indefinitely as x → -∞.

Second piece of function

Substitute the endpoint of the interval into the corresponding function:

$\implies g(3)=-\log_4(3-2)+2=2 \implies (3,2)$

Place an closed circle at point (3, 2).

Graph the curve, adding an arrow at the other endpoint to show it continues indefinitely as x → ∞.

See attached for graph.

The x-intercepts are where the curve crosses the x-axis, so when y = 0.

Set the first piece of the function to zero and solve for x:

$\begin{aligned}g(x) & = 0\\\implies x^3-9x & = 0\\x(x^2-9) & = 0\\\\\implies x^2-9 & = 0 \quad \quad \quad \implies x=0\\x^2 & = 9\\\ x & = \pm 3\end{aligned}$

Therefore, as x < 3, the x-intercepts are (-3, 0) and (0, 0) for the first piece.

Set the second piece to zero and solve for x:

$\begin{aligned}\implies g(x) & =0\\-\log_4(x-2)+2 & =0\\\log_4(x-2) & =2\end{aligned}$

$\textsf{Apply log law}: \quad \log_ab=c \iff a^c=b$

$\begin{aligned}\implies 4^2&=x-2\\x & = 16+2\\x & = 18 \end{aligned}$

Therefore, the x-intercept for the second piece is (18, 0).

So the x-intercepts for the piecewise function are (-3, 0), (0, 0) and (18, 0).

From the graph from part A, and the calculated x-intercepts from part B, the function g(x) is positive between the intervals -3 < x < 0 and 3 ≤ x < 18.

Interval notation: (-3, 0) ∪ [3, 18)

Learn more about piecewise functions here:

brainly.com/question/11562909

3 0

1 year ago