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DIA [1.3K]
3 years ago
11

How to write the algebraic expression (2)(t) in words

Mathematics
1 answer:
Jlenok [28]3 years ago
7 0

Answer:

"The number 8 multiplied by a number. "

"The product of 8 and a number"

"A number times the number 8"

Step-by-step explanation:

This is a long one,

You are going to write the expression using "key words"

Addition: sum, more than, plus, increase, add, older than.

Examples: 4+7

"The sum of 4 and 7"

"7 more than the number 4"

"The number 4 increased by 7"

Etc....

Subtraction: minus, less, subtract, decrease, younger than, and lowered.

Example: 9 - 2

"The number 9 decreased by 2"

"The number 2 younger than 7"

"The number 7 minus 2"

Etc....

Multiplication: times, product, twice, doubled, multiplied, and of.

Example: 4 × 5

"The number 4 multiplied by 5"

"The product of the numbers 4 and 5"

"5 times the number 4"

Etc...

Division: divided by and divided into and Quotient. Pay close attention to the order in which it is written.

Examples: 6 / 3

"The number 6 divided by 3"

"3 divided into the number 6"

Or

"The quotient of the numbers 3 into 6"

Ect...

Expressions with More Than One Operation example:

8y + 14 ...

You could say:

The sum of 8 times a number and 14.

When referring to unknown number i.e. x, y, n, v... you may refer to it a "a number"

Hmmm, best way I can describe it. :)

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-x + 2y = 3<br> 2x – 3y = -6
s2008m [1.1K]

Answer:

x = -3

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Step-by-step explanation:

<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>

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<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

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<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

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<u>x =  \frac{ - 6 + 3y}{2}</u>

<u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

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<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>

<u>2y - 3 =  \frac{ - 6 + 3y}{2}</u>

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

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