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mojhsa [17]
3 years ago
10

A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 m/sec, while the cat can run at

a speed of 24 m/sec.
a
How soon will they meet if they simultaneously start running towards each other?

Please help with this question! I need the answer by tomorrow. Thank you!
Mathematics
2 answers:
Degger [83]3 years ago
6 0

Answer:

3.(703)

Step-by-step explanation:

masha68 [24]3 years ago
4 0

Answer:

The dog will catch the cat at  33.33 sec

Step-by-step explanation:

Let

x------> distance the cat runs before being caught by the dog,

Remember that

The speed is equal to divide the distance by the time

v=d/t

solve for t

t=d/v

so

equate the time

x/24=(200+x)/30

30x=24(200+x)

30x=4,800+24x

30x-24x=4,800

x=4,800/6=800 m

t=d/v=800/24=33.33 sec

or

t=(800+200)/30=1,000/30=33.33 sec

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Answer:

360 ft.

Step-by-step explanation:

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4 0
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5 0
3 years ago
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Factor the following polynomial completely 30y^6+25y^5-10y^4
tia_tia [17]
5y^4 * (6y^2 + 5y-2)
3 0
3 years ago
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aleksandrvk [35]

Answer:

  • Graph B

Step-by-step explanation:

<u>According to data in the table we see pairs of points:</u>

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<u>This gives us the rate of change:</u>

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8 0
2 years ago
Log3 a/3 = ??????????????????????????
Naddik [55]
We have that
<span>Log3 a/3
</span>Rewrite log3(a/3) using the change of base <span>formula

we know that
</span>The change of base rule can be used if a and b are greater than 0 and not equal to 1, and x is greater than 0<span>.
</span>so
loga(x)=<span>logb(x)/<span>logb<span>(a)
</span></span></span>Substitute in values for the variables in the change of base <span>formula
</span>
in this problem
b=10
a=3
x=a/3

log3(a/3)=[log (a/3)]/[log (3)]

the answer is
[log (a/3)]/[log (3)]

8 0
3 years ago
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