Answer:
Step-by-step explanation:
All numbers in scientific notation or standard form are written in the form m × 10n, where m is a number between 1 and 10 ( 1 ≤ |m| < 10 ) and
A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 m/sec, while the cat can run at
2 answers:
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First we simplify, like this: 
So the answer is 7^10<span>
Hope this helped! c:</span>
So the answer is 7^10<span>
Hope this helped! c:</span>
Given that Fawn plants vegetables into garden =
Exact amount of garden is not given so we can assume that amount of garden is 1.
Then remaining amount of garden
Now half of the remaining part of garden that is half of rd part of garden is planted with flowers
so that will be
Hence required fraction for the answer will be 1/6.
Answer:
a) 640 ft
b) 6 seconds (the first time)
c) 14 seconds
Step-by-step explanation:
These problems are solved by using the given equation for the height of the thrown ball with the given values, and solving for the unknown value.
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<h3>a. height after a time</h3>To find the height at a specific time, substitute the time value for t in the height formula and do the arithmetic.
For t = 4, we have ...
h = -16t² +224t = (-16(4) +224)(4) = 160(4) = 640
The height after 4 seconds is 640 ft.
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<h3>b. time for a height</h3>The time required to reach a specific height is found by solving the quadratic equation with h equal to the height value. It can be easier if the equation is in vertex form.
h = -16t² +224t = -16(t² -14t) = -16(t² -14t +49) +784 = -16(t -7)² +784
We want the time to a height of 768 ft, so ...
768 = -16(t -7)² +784
-16/-16 = (t -7)² . . . . . . . . subtract 784, divide by -16
±√1 = t -7 . . . . . . . . . take the square root
t = 7 ±1 = 6 or 8 . . . . . . add 7
The ball will be at a height of 768 ft after 6 seconds, and again after 8 seconds.
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<h3>c. time to reach the ground</h3>The equation from part b applies.
0 = -16(t -7)² +784 . . . . . . . . the height is 0 when the ball is on the ground
-784/-16 = (t -7)² = 49 . . . . . subtract 784, divide by -16
√49 = t -7 . . . . . . . . . . . . . take the positive square root
t = 14 . . . . . . . . . . . . . add 7
The ball will return to the ground after 14 seconds.
