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Sedbober [7]
3 years ago
11

A) assume the following pattern continues.what isometry preserves the pattern?

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

???????????????????

Step-by-step explanation:

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Help me plzzzzzzzzzzz
sammy [17]
I think the answer is 5
7 0
2 years ago
Suppose you cool a pot of soup in a 20°C room. Right when you take the soup off the stove, you measure its temperature to be 180
dezoksy [38]

Answer:

  • 28.3 minutes
  • 53.6°C

Step-by-step explanation:

The temperature of the soup is described by Newton's Law of Cooling, which says the rate of change of temperature is proportional to the difference between the temperatures of the soup and the room. The solution to this differential equation is the exponential function ...

  f(t) = a +b·c^(t/τ)

where a is the room temperature, b is the initial difference in temperature, and c is the fractional change in the difference in temperature over time period τ.

__

<h3>application</h3>

For the given scenario, we find ...

  a = room temperature = 20 . . . . degrees C

  b = (180 -20) = 160 . . . . degrees C

  c = (100 -20)/(180 -20) = 80/160 = 1/2 . . . . in τ = 20 minutes

So, the formula for the temperature of the soup is ...

  f(t) = 20 +160(1/2)^(t/20) . . . . . . . degrees C after t minutes

__

<h3>time to 80°C</h3>

Solving for t when f(t) = 80, we find ...

  80 = 20 +160(1/2)^(t/20)

  3/8 = (1/2)^(t/20) . . . . . subtract 20, divide by 160

  20×log(3/8)/log(1/2) = t ≈ 28.3 . . . take logarithms, divide by coefficient of t

It will take about 28.3 minutes to cool to 80°C.

__

<h3>temp at 45 minutes</h3>

The temperature after 45 minutes is ...

  f(45) = 20 +160(1/2)^(45/20)

  f(45) ≈ 53.6 . . . . degrees C

After 45 minutes the temperature of the soup will be about 53.6°C.

3 0
1 year ago
Read 2 more answers
31. Last month, Sharon's Deli charged the Business Club $231
finlep [7]

Answer:hello the answer is C. 7$

Step-by-step explanation:

4 0
3 years ago
Find UV (Pic Stated Below)
natta225 [31]

Answer:

UV=29

Step-by-step explanation:

In right triangles AQB and AVB,

∠AQB = ∠AVB ...(i)  {Right angles}

∠QBA = ∠VBA ...(ii)  {Given that they are equal}

We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle


∠AQB+∠QBA+∠BAQ=180 ...(iii)

∠AVB+∠VBA+∠BAV=180 ...(iv)


using (iii) and (iv)

∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV

∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV  (using (i) and (ii))

∠BAQ=∠BAV...(v)


Now consider triangles AQB and AVB;

∠BAQ=∠BAV  {from (v)}

∠QBA = ∠VBA {from (ii)}

AB=AB  {common side}

So using ASA, triangles AQB and AVB are congruent.

We know that corresponding sides of congruent triangles are equal.

Hence

AQ=AV

5x+9=7x+1

9-1=7x-5x

8=2x

divide both sides by 2

4=x

Now plug value of x=4 into UV=7x+1

UV=7*4+1=28+1=29

<u>Hence UV=29 is final answer.</u>

7 0
3 years ago
5, 3, 2, 6, 7, 9, 1, 15, 4, 2, 3, 3, 9, 5, 1, ?
Shkiper50 [21]

Answer:

I have no idea thank you for the points

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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