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loris [4]
4 years ago
13

-9(5-2)-111÷3 show all work ​

Mathematics
2 answers:
kompoz [17]4 years ago
5 0

Answer:

-9·3-111 ÷3

-27-111 ÷3

-27-37= -64

the answer is -64

Tasya [4]4 years ago
3 0

Answer:

-74

Step-by-step explanation:

First: 5-2=3

-9*3=-27

111÷3=37

Then do -27-37=-74

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Which, if any, pair of sides are parallel? AB II DC and AD II BC Cannot be determined AB II DC only AD II BC only
zaharov [31]

Answer:

120%

Step-by-step explanation:

5 0
3 years ago
Liam has a bag of b beads. He gives 20 beads to his sister. He then makes 4 necklaces with the same of beads on each necklace us
grin007 [14]

Given :

Liam has a bag of b beads.

He gives 20 beads to his sister.

He then makes 4 necklaces with the same of beads on each necklace using all of the remaining beads.

To Find :

Write an expression that represents the number of beads on each necklace.

Solution :

Number of necklace remains after giving 20 beads to his sister is ( b - 20 ).

Number of beads on each necklace using all of the remaining beads  is :

N=\dfrac{b-20}{4}

Hence, this is the required solution.

6 0
3 years ago
Really just free points, should be easy
Maksim231197 [3]

15 - 2(- 13s + 3) = 9s - 9 + 16s

15 + 26s - 6 = 25s - 9

9 + 26s = 25s - 9

26s - 25s = -9 - 9

s = - 18

3 0
3 years ago
Read 2 more answers
The value of x in the equation log(x-1)9=2 is
mel-nik [20]
\log_{(x-1)} 9=2

the domain:
x-1 >0 \ \land \ x-1 \not=1 \\
x>1 \ \land \ x \not= 2 \\
x \in (1; 2) \cup (2;+\infty)

the equation:
\log_{(x-1)}9=2 \\
(x-1)^2=9 \\
\sqrt{(x-1)^2}=\sqrt{9} \\
|x-1|=3 \\
x-1=3 \ \lor \ x-1=-3 \\
x=4 \ \lor \ x=-2

4 is in the domain
-2 is not in the domain

The answer:
x=4

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:
x=\sqrt{5x+24} \\
-3=\sqrt{5 \times (-3)+24} \\
-3=\sqrt{-15+24} \\
-3=\sqrt{9} \\
-3=3
It's not true so -3 isn't a solution to this equation.
4 0
3 years ago
Read 2 more answers
Answer pls I need it
-BARSIC- [3]

This is a 1:3 ratio of girls to boys so we need to find one part by dividing 236 by 4 giving us 59 and then multiplying by the parts with boys which is 3 so 59*3=177 therefore there are 177boys in the class

3 0
4 years ago
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