X = smallest; x + 2 = middle, and x + 4 = largest
x + 2(x+2) = 20 + x + 4
x + 2x + 4=24 +x
3x + 4 = 24 + x
2x = 20
x = 10
so the three integers are 10, 12, and 14
It’s the last answer choice y=2/3x
X + x + 165 = 1315
2x + 165 = 1315
subtract 165 from both sides
2x = 1150
divide both sides by 2
x = 575
January 575
February 575 + 165 = 740
640 Diveded by 8 = 80 and 80 diveded by 6 = 13 R2
