Answer:
3.2
Step-by-step explanation:
Given the coordinates
X(4, -3)
Y(2, 1.5)
A(3, 3)
Z(4,-1)
We are to find the distance from point A to XZ
First let us get the coordinate XZ
According to vector notation XZ = Z-X
XZ = (4,-1)-(4,-3)
XZ = [(4-4),-1-(-3)]
XZ = (0, 2)
Next is to find the distance from A(3, 3) to XZ(0,2) using the formula for calculating the distance between two points.
D = √(x2-x1)²+(y2-y1)²
x1 = 3, y1 = 3, x2 = 0, y2 = 2
D = √(0-3)²+(2-3)²
D = √9+1
D = √10
D = 3.16
Hence the distance from point A to XZ to nearest tenth is 3.2
Answer:
The answer should be 113.04
The first box is the answer to your question.
Answer:
y = -2x + 3
y = -1/2x + 5
Step-by-step explanation:
- So the best way to solve is to come up with two slopes, I'd prefer 2 perpendicular slopes because perpendicular lines only cross once hence one solution guaranteed
- so say we choose a slopeA = 2 and slopeB = -1/2, the slopes are perpendicular only if when you multiply them you get -1
- then we use the slope intercept form of an equation y = mx + b
- we make up two equations y = -2x + b and y = -1/2x + b , now we can just make up number for b so the two equations are
- y = -2x + 3
- y = -1/2x + 5
- Then we solve them by substituting for y so
- -1/2x + 5 = -2x + 3 and x = -4/3
- and then we put this to get y in either equation
- y = -2(-4/3) + 3
- y = 17/3
- So the equations work
Answer:
B on edge
Step-by-step explanation:
just got it wrong
