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3 years ago

Hi please please help me

Mathematics

2 answers:

Kaylis [27]3 years ago

6 0

Answer:

141.12 cm^2

Step-by-step explanation:

Since the area of a trapezoid is the average of the bases multiplied by the height, we can just plug these numbers into the equation! Since the average of 10.2 and 12.2 is 11.2, and the height is 12.6, we multiply them to get the area to be 141.12 cm^2.

Oksi-84 [34.3K]3 years ago

6 0

Answer:

141.12cm^2

Step-by-step explanation:

I do not know if this is the correct way to do it, but I split the trapezoid in half, then putting it on top of each other to create a rectangle, which is (10.2cm+12.2cm)(12.6cm/2)

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Find the area of each sector 3m 150°

Oksanka [162]

Answer:

$\frac{150}{360} \times \pi \times {3}^{2} \\ 2.4 \times \pi \times 9 = 11.780 {m}^{2}$

7 0

3 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

How to solve 45=6n+3n

Naddik [55]

45 = 6n + 3n
45 = 9 n
dividing 9 on other side
45 / 9 = n
5 = n
or
n = 5 answer..

5 0

3 years ago

Read 2 more answers

I don’t know what this is

svet-max [94.6K]

From the graph given

For f(x), where x = 3, on the graph f(3) is

$f(3)=6$

For g(x), where x = 3, on the graph g(3) is

$g(3)=6$

Hence,

$f(3)=g(3)$

The answer is the second option

3 0

1 year ago

The variable Z is directly proportional to X. when X is 15, Z has the value of 45. what is the value of Z when X=23

IrinaVladis [17]

$If\ Z\ is\ directly\ proportional\ to\ X\ then\ \frac{Z}{X}=const.\\------------------------\\X=15\ and\ Z=45\\\\X=23\ and\ Z=?\\\\\frac{Z}{23}=\frac{45}{15}\to\frac{Z}{23}=3\ \ \ \ |multiply\ both\ sides\ by\ 23\\\\\huge\boxed{Z=69}$

8 0

3 years ago