HELP ME PLZZ I NEED HELP WITH THIS
1 answer:
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Answer:
1/2
Explanation:
This question involves a single gene coding for feather color in chickens. The black allele (B) is incompletely dominant over the white allele (W). This means that the allele B will not mask the phenotypic expression of allele W, hence, a third intermediate blue phenotype (BW) will be produced.
According to the question, if two blue chickens are crossed i.e. BW × BW, the gametes B and W will be produced by each parent. Using these gametes in a punnet square (see attached image), the following offsprings will be produced:
BB, BW and WW in the ratio 1:2:1
BB is black, BW is blue, WW is white. Hence, the probability of producing a blue chicken from this cross is 1/2.
1. where in a population:
p - the frequency of the <em>A</em> allele
q - the frequency of the <em>a</em> allele
- the frequency of the <em>AA</em> homozygous genotype
- the frequency of the <em>aa</em> homozygous genotype
2pq - the frequency of the <em>Aa</em> heterozygous genotype
A population at equilibrium will have the sum of all the alleles at the locus equal to 1.
2. Conditions:
A. The breeding population must be large
B. No natural selection
C. The mating must occur randomly
D. No mutations to cause changes in allelic frequency.
E. No changes in allelic frequency due to immigration or emigration.
3. By comparing the actual genetic structure of a population with what we would expect from a Hardy-Weinberg equilibrium, we can determine how much it deviates from the baseline provided by the mathematical model. Depending on how large the deviation is, one or more of the model's assumptions are being violated. Thus, we can attempt to determine which one.