People who work in Health Science career clusters can expect a career that deals with promoting health to treating diseases. Some examples of professions in this cluster include dietitians, neurologists, and biomedical engineers. With a wide variety of professions that are included in this cluster, the workplaces where these individuals can work are also equally as diverse.
Thus, the best answer for the question is (C) workplaces in this cluster include nonprofit hospitals, government-run clinics, and private physicians' offices.
Answer:
The exception is due to vacation.
Explanation:
This is an example of a right answer, while, yes the individual must be registered in Canada, the exception is due to vacation.
Each type of employment has been matched with its definition thus:
- Frictional unemployment: Unemployment associated with workers who are between jobs
- Cyclical unemployment: Unemployment resulting from mismatches between employer needs and employee skills.
- Structural unemployment: Unemployment associated with the highs and lows of the business cycle.
There are different causes of employment. Frictional unemployment is the timeframe between the period an individual lost his job and seeks another.
Structural unemployment is a result of inconsistencies in the labor market.
Cyclical unemployment occurs when the demand from the employee is not met with the skills of the employer.
Learn more about unemployment here:
brainly.com/question/305041
Answer:
$8,770.00
Explanation:
In this question we use the present value formula i.e shown in the attachment below:
Data provided in the question
Future value = $0
Rate of interest = 0.48%
NPER = 4 years × 12 months = 48 months
PMT = $205
The formula is shown below:
= -PV(Rate;NPER;PMT;FV;type)
So, after solving this, the answer would be $8,770.00
Answer:
Explanation:
Experiments were performed for 240 people, 60 people test positive.
Step 1: we calculate the sample proportion; p= 60/240= 0.25.
Step 2: calculate the standard error for the sample, which is the square root of sample proportion,p = p(1-p)/n, n=100
0.25(1-0.25)/100
= 0.04.
Step 3: calculate the test statistics; assuming the hypothesis test percentage is 25%
Then, we say 0.25-1=0.75
-0.75/0.04
= -1.875.
In particular, the sample results are -1.875 standard error.
Probability of Z is less than -1.875.
Look up it value in the Z table
