Answer:
Step-by-step explanation:
to solve this system of equations we will add them
x-3y=-12
2x+3y=3 now +3y-3y=0
3x=-12+3
3x=-9
x=-3
plug in the first equation
-3-3y=-12
-3y=-12+3
-3y=-9
y=3
Answer:
#1: inequality form: x ≤ –1 or x ≥ 2
interval notion: ( -∞,-1] U [2,∞)
#2: false/no solution
#3: A) point form: (3,9)(-1,1)
equation form: x= 3,y=9 and x= -1,y=1
B)point form: (1,7)(7,1)
equation form: x=1,y=7 and x=7,y=1
Step-by-step explanation:
#1: solve for x by simplifying both sides of the inequality, then isolating the variable.
#2: N/A
#3: solve for the first variable in one of the equations, then substitute the results into the other question.
Range is the outputs possible
w(r(x))=(2-x^2)-2
w(r(x))=2-x^2-2
w(r(x))=-x^2
therefor the range is from 0 to -∞