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Nonamiya [84]
3 years ago
7

Question 1 of 10

Mathematics
2 answers:
Korvikt [17]3 years ago
7 0

Correct answer is B, because you have to do is to addition similar monomials.

Naddika [18.5K]3 years ago
3 0

Answer:

B. 6x2+x+7

Step-by-step explanation:

combine like terms

3x^2+3x^2= <u>6x^2</u>

<u>x</u>

3+4=<u>7</u>

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Someone pls help asap this is due tmrw !!<br><br> x - 3y = -12<br> 2x + 3y = 3
hram777 [196]

Answer:

Step-by-step explanation:

to solve this system of equations we will add them

x-3y=-12

2x+3y=3 now +3y-3y=0

3x=-12+3

3x=-9

x=-3

plug in the first equation

-3-3y=-12

-3y=-12+3

-3y=-9

y=3

4 0
3 years ago
1.Solve the inequality (x-2)(x+1) ≥ 0 .
scoray [572]

Answer:

#1: inequality form: x ≤ –1 or x ≥ 2

interval notion: ( -∞,-1] U [2,∞)

#2: false/no solution

#3: A) point form: (3,9)(-1,1)

equation form: x= 3,y=9 and x= -1,y=1

B)point form: (1,7)(7,1)

equation form: x=1,y=7 and x=7,y=1

Step-by-step explanation:

#1: solve for x by simplifying both sides of the inequality, then isolating the variable.

#2: N/A

#3: solve for the first variable in one of the equations, then substitute the results into the other question.

5 0
3 years ago
Solve v times w squared+ y= x. Solve for w. Please show me how you got the answer!
faltersainse [42]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

let's solve for " w "

  • vw {}^{2}  + y = x

  • vw {}^{2}  = x - y

  • {w}^{2}  =  \dfrac{x - y}{v}

  • w =  \sqrt{ \dfrac{x - y}{v} }
6 0
3 years ago
Read 2 more answers
If r(x) = 2 – x2 and w(x) = x – 2, what is the range of w(r(x))
Paladinen [302]
Range is the outputs possible
w(r(x))=(2-x^2)-2
w(r(x))=2-x^2-2
w(r(x))=-x^2

therefor the range is from 0 to -∞
5 0
3 years ago
Read 2 more answers
If x&gt;2,then x2-x-6/x2-4=
statuscvo [17]
\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)
---------------------\\x^2-4=x^2-2^2=(x-2)(x+2)\\-------------------\\\\(*)=\frac{(x+2)(x-3)}{(x-2)(x+2)}=\frac{x-3}{x-2}


6 0
3 years ago
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