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vlada-n [284]
2 years ago
11

What is the simplest form of x²+5x-6/x²+9x+18

Mathematics
1 answer:
Lyrx [107]2 years ago
4 0

Answer:

(x - 1) / (x + 3).

Step-by-step explanation:

x²+5x-6/x²+9x+18

Factoring top and bottom:

= (x + 6)(x - 1) / (x + 6)(x + 3)   (x + 6) is common, so:

= (x - 1) / (x + 3) (answer).

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Answer:

<h3>Rational numbers</h3>

Step-by-step explanation:

A rational number is a number that can be written as a ratio of two integers. The are expressed as fractions. Given the value 8/9, this value is a fraction and is written as a ratio of two integers 8 and 9.

The value is neither a real number, nor an integer because integers and whole numbers are not expressed as fractions.

Natural numbers are also whole numbers starting from 1 and above. Hence 8/9 is not a natural number as well.

Note that irrational numbers are also classified as real numbers and they can not be written as a ratio of two integers.

Conclusively, 8/9 is only classified as a rational number

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find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
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Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

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