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Serga [27]
3 years ago
15

How do I find the ratio of the first measurement to the second measurement ?

Mathematics
1 answer:
Alla [95]3 years ago
7 0
1\ ft=12\ inches\\2\ ft\ 4\ in\ =\ 2\cdot12+4=24+4=28\ in\\\\Ratio:\\\\28:10\ ->\ 14:5\\\\Ratio\ is\ equal\ 14:5
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If John has 1107 bars of chocolate and wants to give each of his 10 friends an even amount each, what would each friend get? Wha
Nutka1998 [239]
Divide 1107 by 10, for example:

1107/10= 110.7

The decimal point means the remainder, this means John will only get 7 chocolate bars. 

If You want it split evenly between ALL of them, divide by 1107 by 11, for example: 

1107/11= 100.6, which would leave six bars left, so I think the logical offer would be the first answer I gave you. 

I hope this helped! 
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son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

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\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

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raketka [301]

Answer:

3/4 becomes 9/12

5-9 is -4 》-4/12 = -1/3 a.k.a C

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