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Sedbober [7]
3 years ago
10

Please answer I will give you brainliest!!! Find the angles of the rhombus if the ratio of the angles formed by diagonals and th

e sides of the rhombus is 6:5
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
7 0

Answer:

one angle : 6x=6(90/11)=540/11 (49.1 rounded to the nearest tenth)

other angle=5(90/11)=450/11 (41 degrees rounded to the nearest ones)

Step-by-step explanation:

ratio of the angles 6:5

when you draw diagonal inside a rhombus it creates four right angled triangle

one angle=90

6x+5x=90 ( the other angles is complimentary)

11x=90

x=90/11

one angle : 6x=6(90/11)=540/11 (49.1 rounded to the nearest tenth)

other angle=5(90/11)=450/11 (41 degrees rounded to the nearest ones)

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A rectangle has its base on the x axis and its upper two vertices on the parabola y = 9 − x2. (a) Draw a graph of this problem.
gtnhenbr [62]

Answer:

  • (a) see attached
  • (b) width: 2x; height: y = 9-x²
  • (c) A=2x(9-x²) . . . 0 ≤ x ≤ 3
  • (d) dA/dx = -6x² +18; x=±√3
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Step-by-step explanation:

(a) The attachment shows the graph of the parabola in blue. It also shows an inscribed rectangle in black.

(b) The upper right point of the rectangle is shown in the attachment as (x, y). The dimension y is the height of the rectangle. The x-dimension is half the width of the rectangle, which is symmetrical about the y-axis. Hence the width is 2x.

(c) As with any rectangle, the area is the product of length and width:

... A = (2x)(9 -x²) . . . . . the attachment shows a graph of this

... A = -2x³ +18x . . . . . expanded form suitable for differentiation

A suitable domain for A is where both x and A are non-negative: 0 ≤ x ≤ 3.

(d) The derivative of A with respect to x is ...

... A' = -6x² +18

This is defined everywhere, so the critical values will be where A' = 0.

... 0 = -6x² +18

... 3 = x² . . . . . . . divide by -6, add 3

... √3 = x . . . . . . . -√3 is also a solution, but is not in the domain of A

(e) The rectangle will have its largest area where x=√3. That area is ...

... A = 2x(9 -x²) = 2√3(9 -(√3)²) = 2√3(6)

... A = 12√3 . . . . square units . . . . ≈ 20.785 units²

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