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san4es73 [151]
3 years ago
5

Let U = {a, b, c, e, d, e, f, g, h, i, j, k}; A = {a, b, e, f, h, j}; B = {b, c, d, f, j}. Draw a Venn Diagram with a rectangle

for the Universal set given. Label and mark elements for set A and set B.

Mathematics
1 answer:
marishachu [46]3 years ago
6 0
<h3>Answer: Venn Diagram is below</h3>

The rectangle represents the universal set (marked as "set U"). Everything is contained in this rectangle.

Circle A represents set A = {a, b, e, f, h, j}

Circle B represents set B = {b, c, d, f, j}

The common elements between the two sets are {b, f, j}, so we'll write these three values in the overlapping portion of the two circles.

The items {a,e,h} will go in circle A, but not in the overlapping portion since they are found only in set A.

Similarly we'll have {c,d} go in circle B but not in the overlapping portion since these items are only found in set B.

The remaining terms {g, i, k} go outside both circles, but inside the rectangle, because neither of these elements are in set A or set B.

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Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0
2 years ago
Twice the difference between a number and 10 is equal to 6 times the number plus 16. What is the number?
oksano4ka [1.4K]
This is a lot of math to write.... so I'll just say the answer is -21 :D
8 0
3 years ago
The total cost of 4 goldfish and 3 guppies is $29. 3 goldfish and 5 guppoes cost $30. How much does each cost
Aneli [31]

let the goldfish be x and the guppies be y

4x + 3y = 29...equ(1)

3x + 5y = 30...equ(2)

multiplying equation 1 by 5 and equation 2 by 3

20x + 15y = 145...equ(1)

9x + 15y = 90...equ(2)

subtracting equation 2 from 1

11x = 55

∴x = 5

 substituting the value of x into equation

4(5) + 3y = 29

20 + 3y = 29

3y = 9

∴y =3

5 0
3 years ago
Solve for x. 5 x − 19 ≤ 1 OR − 4 x + 3 &lt; − 6
k0ka [10]

5x - 19 \leqslant 1

change

\leqslant  \: to \:  =

given you

5x - 19 = 1

making x the subject by transferring the -19 to the right hand side of the equation

5x = 19 + 1

5x = 20

dividing through by 5

\frac{5x}{5}  =  \frac{20}{5}

x = 4

{{x:x  \leqslant 4}}

also given

- 4x + 3 < -  6

change the operation sign to =

- 4x + 3 =  - 6

- 4x =  - 6 - 3

- 4x =  - 9

dividing through by -4

\frac{ - 4x}{ - 4}  =  \frac{ - 9}{ - 4}

x =  \frac{9}{4}

so the truth set is

{x:x>9/4}.

The < sign changes to > because we divided by a negative number when solving for x

4 0
3 years ago
In the right triangle shown, mZA = 45° and AB = 12.<br> B<br> 12<br> 45<br> How long is BC?
wel

Answer:

6sqrt(2)=8.5

Step-by-step explanation:

Using pythagoras theorem

5 0
3 years ago
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