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3 years ago

Simplify the following expression by combining like term show your work. 4x-6x

Mathematics

1 answer:

ASHA 777 [7]3 years ago

6 0

-2x

6 - 4 = 2

BOTH NUMBERS HAVE VARIABLE OF X SO THE X WILL GO ON THE 2 ALSO

6x - 4x = 2x

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Convert to a decimal: 52%<br> 0.052<br> 5.20<br> O 52<br> .0052

scoundrel [369]

Very interesting question, i’m happily here to answer it for you The answer you might be looking for is
decimal: 0.052
Fraction:13/250
Percentage: 5.2%

Have a blessed day God bless.

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2 years ago

Read 2 more answers

5. Write the slope-intercept form of an equation for a line with y-intercept 9 and

Alika [10]

Answer:

y=-3x+9

Step-by-step explanation:

y=mx+b

m=slope

b=y-intercept

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2 years ago

A baseball is hit with an initial upward velocity of 70 feet per second from a height of 4 feet above the ground. The equation h

Katyanochek1 [597]

To solve you need to set the equation equal to 6 (the height at which the player caught the ball.

6 = -16t^2 + 70t + 4

Next put the equation in standard form by subtracting 6 from both sides

-16t^2 + 70t - 2 = 0

This equation can be simplified by dividing by 2

-8t^2 + 35t - 1 = 0

This equation cannot be factored, but we can use the quadratic formula to find a value for x. Using the equation above we can find the values for a=-8, b = 35 and c = -1.

using the quadratic formula we can solve for x

-b +/- sqrt(b^2 - 4ac)
-------------------------------
2a

The solutions are

0.03 and 4.35. as 0.03 seems an unrealistic time to hit and catch a baseball we would expect the time to be 4.35 seconds.

8 0

3 years ago

Evaluate the integral ∫2032x2+4dx. Your answer should be in the form kπ, where k is an integer. What is the value of k? (Hint: d

faltersainse [42]

Here is the correct computation of the question;

Evaluate the integral :

$\int\limits^2_0 \ \dfrac{32}{x^2 +4} \ dx$

Your answer should be in the form kπ, where k is an integer. What is the value of k?

(Hint: $\dfrac{d \ arc \ tan (x)}{dx} =\dfrac{1}{x^2 + 1}$ )

k = 4

(b) Now, lets evaluate the same integral using power series.

$f(x) = \dfrac{32}{x^2 +4}$

Then, integrate it from 0 to 2, and call it S. S should be an infinite series

What are the first few terms of S?

Answer:

(a) The value of k = 4

(b)

$a_0 = 16\\ \\ a_1 = -4 \\ \\ a_2 = \dfrac{12}{5} \\ \\a_3 = - \dfrac{12}{7} \\ \\ a_4 = \dfrac{12}{9}$

Step-by-step explanation:

(a)

$\int\limits^2_0 \dfrac{32}{x^2 + 4} \ dx$

$= 32 \int\limits^2_0 \dfrac{1}{x+4}\ dx$

$=32 (\dfrac{1}{2} \ arctan (\dfrac{x}{2}))^2__0$

$= 32 ( \dfrac{1}{2} arctan (\dfrac{2}{2})- \dfrac{1}{2} arctan (\dfrac{0}{2}))$

$= 32 ( \dfrac{1}{2}arctan (1) - \dfrac{1}{2} arctan (0))$

$= 32 ( \dfrac{1}{2}(\dfrac{\pi}{4})- \dfrac{1}{2}(0))$

$= 32 (\dfrac{\pi}{8}-0)$

$= 32 ( (\dfrac{\pi}{8}))$

$= 4 \pi$

The value of k = 4

(b) $\dfrac{32}{x^2+4}= 8 - \dfrac{3x^2}{2^1}+ \dfrac{3x^4}{2^3}- \dfrac{3x^6}{2x^5}+ \dfrac{3x^8}{2^7} -... \ \ \ \ \ (Taylor\ \ Series)$

$\int\limits^2_0 \dfrac{32}{x^2+4}= \int\limits^2_0 (8 - \dfrac{3x^2}{2^1}+ \dfrac{3x^4}{2^3}- \dfrac{3x^6}{2x^5}+ \dfrac{3x^8}{2^7} -...) dx$

$S = 8 \int\limits^2_0dx - \dfrac{3}{2^1} \int\limits^2_0 x^2 dx + \dfrac{3}{2^3}\int\limits^2_0 x^4 dx - \dfrac{3}{2^5}\int\limits^2_0 x^6 dx+ \dfrac{3}{2^7}\int\limits^2_0 x^8 dx-...$