How much would 500$ invested at 9% interest compounded annually be worth after 4 years?
1 answer:
Answer:
$705.79
Step-by-step explanation:
(see attached for reference)
the formula for compound interest is
A = P [1 + (r/n) ]^(nt)
Where:
P = Principal Amount = $500
r = annual interest rate = 9% = 0.09
t = 4 years
n = 1 (compounded annually)
A = 500 [1 + (0.09/1) ]^(1 x 4)
A = 500 [1 + 0.09 ]^(4)
A = 500 [1.09 ]^(4)
A = $705.79
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Step-by-step explanation:
The angles form a straight angle, so y = 180 - 80 - 60 = 40.
First write it in vertex form :-
y= a(x - 2)^2 + 3 where a is some constant.
We can find the value of a by substituting the point (0.0) into the equation:-
0 = a((-2)^2 + 3
4a = -3
a = -3/4
so our equation becomes y = (-3/4)(x - 2)^2 + 3
Answer:
x = 10
Step-by-step explanation:
=> 4x + 1 + 2x = 61
=> 6x = 61 - 1
=> 6x = 60
=> x = 60/6
=> x = 10
<u>Hence</u><u> </u><u>the</u><u> value</u><u> of</u><u> x</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u> </u><u>.</u>
A,b are 8,2. its an easy guess.
now that makes it easy
