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Verizon [17]
2 years ago
11

I dont get what its asking

Mathematics
1 answer:
Tomtit [17]2 years ago
8 0
First u need to know what distributive property is so Distributive Property<span> is an algebra </span>property<span> which is used to multiply a single term and two or more terms inside a set of parentheses. Take a look at this problem. 2(3 + 6) 
 
thats distributive property  so.... if u need more help then ask im happy to help</span>
You might be interested in
The graph of a linear system is shown. What is the solution the linear system?
Mkey [24]

Answer:

y=3x-1 and y=3x+1

Step-by-step explanation:

y=mx+b form

m stands for the slope which is rise over run.

b stands for the y intercept. where the line intersects with the y axis.

7 0
2 years ago
A boat is heading towards a lighthouse, whose beacon-light is 139 feet above the
Novay_Z [31]

The horizontal distance between light house and boat is 1588.78 feet approximately.

The figure is given by,

Here, AB  = height of the lighthouse bacon light above the water = 139 feet

Now angle ACB = 5 degree

Let the horizontal distance of light house from the boat = BC = x feet

So by trigonometric function we get,

tan 5 = AB/BC

tan 5 = 139/x

x = 139/tan 5 = 1588.78 (approximately)

Hence the horizontal distance between light house and boat is 1588.78 feet approximately.  

To know more about Trigonometric Function refer to:

brainly.com/question/1143565

#SPJ9

5 0
1 year ago
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
3 years ago
Maggie sells homemade cookies. on a dozen cookies she spend 0.50 on flour, 0.70 on sugar, 0.40 on eggs,and 0.40 on packaging if
Art [367]

Using the profit concept, it is found that she makes a profit of $4 selling a dozen cookies for six dollars.

<h3>What is a profit?</h3>


The profit is given by the <u>subtraction of the revenue by the total costs</u>.

In this problem:

  • For the dozen cookies, she earned a revenue of 6 dollars.
  • In all, the total cost of the 12 cookies was of 0.5 + 0.7 + 0.4 + 0.4 = 2 dollars.

6 - 2 = 4, hence she makes a profit of $4.

More can be learned about the profit concept at brainly.com/question/4001746

5 0
2 years ago
Which of the following is a valid comparison between the possible minimum and maximum values of the function y = -x2 + 4x - 8 an
Arturiano [62]

Answer:

The maximum value of the equation is 1 less than the maximum value of the graph

Step-by-step explanation:

We have the equation y=-x^2+4x-8.

We can know that this graph will have a maximum value as this is a negative parabola.

In order to find the maximum value, we can use the equation x=\frac{-b}{2a}

In our given equation:

a=-1

b=4

c=-8

Now we can plug in these values to the equation

x=\frac{-4}{-2} \\\\x=2

Now we can plug the x value where the maximum occurs to find the max value of the equation

y=-(2)^2+4(2)-8\\\\y=-4+8-8\\\\y=-4

This means that the maximum of this equation is -4.

The maximum of the graph is shown to be -3

This means that the maximum value of the equation is 1 less than the maximum value of the graph

6 0
3 years ago
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