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DerKrebs [107]
4 years ago
11

Solve for xxx. Write the smaller solution first, and the larger solution second. x^2 + 9x + 18 = 0x 2 +9x+18=0x, squared, plus,

9, x, plus, 18, equals, 0 \text{smaller }x =smaller x=start text, s, m, a, l, l, e, r, space, end text, x, equals \text{larger } x =larger x=start text, l, a, r, g, e, r, space, end text, x, equals
Mathematics
2 answers:
pshichka [43]4 years ago
6 0

Answer:

X=2 and x=9

Step-by-step explanation:

motikmotik4 years ago
3 0

Answer:

x = -6 or x = -3

Step-by-step explanation:

x² + 9x + 18 = 0

(x + 3) (x + 6) = 0

x = -6 or x = -3

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18-4y

Step-by-step explanation:

18 -4y because your start with 18, and each day 4 get eaten. so day 2 (4*2) there will be 8 less, etc, etc

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Suppose there are eight different management trainee positions to be assigned to eight employees in a company’s junior managemen
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Solve for y . 2−5=−12 2 x - 5 y = - 12
Brut [27]

Answer:

This answer can not answer

Step-by-step explanation:

What is in between the 12 and 2x

4 0
3 years ago
The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds,What perc
soldier1979 [14.2K]

Answer:

57.62% of players weigh between 180 and 220 pounds

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 25

What percent of players weigh between 180 and 220 pounds

We have to find the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 180.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{25}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881

X = 180

Z = \frac{X - \mu}{\sigma}

Z = \frac{180 - 200}{25}

Z = -0.8

Z = -0.8 has a pvalue of 0.2119

0.7881 - 0.2119 = 0.5762

57.62% of players weigh between 180 and 220 pounds

4 0
3 years ago
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