The perimeter of the square patio is the sum of its side lengths
The length of the patio is: 8x + 2
The given parameters are:


The perimeter of a square is:

So, we have:

Divide both sides by 4

Hence, the length of the patio is: 8x + 2
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66 is the anwer I think I'm not for sure I hope this helps and you get it right
Each ream weighs 5 lb . so, reducing 10 lb means removing 2 reams from the 12. so, how do we arrange the 10 reams so that its easy to carry?
i thinks that 3 stacks will not work as it wont be a symmetric arrangement as 1 will be left out. So, 2 stacks of 5 each would be easy to carry. but the stacks should be placed in such a way that the lengths are parallel to each other and not in-line which would increase the length making it comparatively longer. its easier to hold a (2*8.5,11,2*5=17,11,17)compact box.
No sé lo siento esqje necesito mas puntos lol hahaha
There are a few ways to solve this. The method I will use is the substitution method. Since they give us a "y = " statement, we can replace the y in the second equation with what it gives us to the right of the equal sign.
- 3x + 6(- 2x - 1) = 24
Simplify by using the distributive property.
- 3x + 6(- 2x) + 6(- 1) = 24
- 3x - 12x - 6 = 24.
Combine like terms
- 15x - 6 = 24
Add 6 to each side.
- 15x = 30
Divide both sides by - 15 to isolate variable X
x = 30 / - 15
x = - 2.
Now plug in the x-value we've found back into the first equation.
y = - 2( - 2) - 1
y = 4 - 1
y = 3
Your answer is (- 2, 3)