<h3><u>Question:</u></h3>
Serena uses chalk to draw a straight line on the sidewalk. The line is 1/2 ft long. She wants to divide the line into sections that are each 1/8 ft long. How many sections will the line be divided into?
<h3><u>Answer:</u></h3>
The number of sections that the line is divided is 4
<h3><u>Solution:</u></h3>
Given that, Serena uses chalk to draw a straight line on the sidewalk
The line is 1/2 ft long. She wants to divide the line into sections that are each 1/8 ft long
From given,

To find: Number of sections can be made
The number of sections that can be made is found by dividing the total length of line by length of each section

Substituting the values, we get,

Thus number of sections that the line is divided is 4
This is an obtuse triangle because one angle of it is greater than 90 degrees :)
Based on the given description above, here is how we are going to solve it.
Let n be the number of years. So the equation will be like this.
37000n + 1500n = 1025000
Now let us solve for n.
38500n = 1025000 <<<divide by sides by 38500 and the result is
n=26.62
Therefore, it will take 26 years and 6 months before you made a total salary of 1,025,000 dollars. Hope that this answer helps.
Answer:
see explanation
Step-by-step explanation:
(1)
Given
g(r) = (r + 14)² - 49
To obtain the zeros, let g(r) = 0 , that is
(r + 14)² - 49 = 0 ( add 49 to both sides )
(r + 14)² = 49 ( take the square root of both sides )
r + 14 = ±
= ± 7 ( subtract 14 from both sides )
r = - 14 ± 7, then
r = - 14 - 7 = - 21 ← smaller r
r = - 14 + 7 = - 7 ← larger r
(2)
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
g(r) = (r + 14)² - 49 ← is in vertex form
with vertex = (- 14, - 49 )
Using x and y as the numbers
x+y=25 -------#1
x-y=9 -------#2
Using addition of #1 and #2
x+y+x-y= 25+9
2x+0y=34
2x=34
x=17
Using the value of x and plugging said value into #1 or #2, we can find y
x=17
x+y=25
17+y=25
y=8
OR
x-y=9
17-y=9
-y=-8
y=8
The numbers are 8 and 17