Answer:
B) To represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
Step-by-step explanation:
Here the point A is given as 3 on number line.
Point B is given as -5 on number line.
To find : IA-BI
The distance between any two point A and B is given as IA-BI.
Now, to find the absolute value:
IA-BI = I (3) - (-5)I
or, IA-BI = I (3) + 5I = I8I
= 8 units
or, IA-BI = 8 units
Hence, on the number line, the distance between -5 and 3 is 8 units.
And, to represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
Answer:correct answer =0
Step-by-step explanation:
Step 1
5x - (x + 3)2
Putting the coefficient of x =2 in the equaton we have
5(2) - (2 + 3)2
Solving out
5(2) - (5)2
= 10- 10
=0
Step 2
Amir's mistake was in the multiplication and wrong use of the negative sign of the bolded below
5(2) - (2 + 3)2 = 10 + (-5)2 = 10 + 25 = 35
-(5)2 cannot give 25 instead 10, so him getting a 25 and wrong use of the negative and positive made his answer wrong.
The right answer as calculated in step 1 = 0
For this case, the first thing we must do is define variables.
We have then:
x: number of checks.
y: total cost.
We now write the linear function that represents the problem.
We have then:

Then, Jerome issues 10 checks in a month.
Therefore, we evaluate the function for x = 10.
We have then:
Answer:
a monthly checking account will cost him about:
y = 12.5 $