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MrRa [10]
3 years ago
7

How many ways can 6 people be chosen and arranged in a straight line if there are 8 people to choose from? 720 20,160 40,320 48?

Mathematics
2 answers:
Rudik [331]3 years ago
5 0
The number of permutations of 8 people taken 6 at a time is given by:
8P6=\frac{8!}{(8-6)!}=20,160

blagie [28]3 years ago
5 0

Answer: 28ways

Step-by-step explanation:

This has to do with selection i.e selecting 6people from pool of 8 people

Since combination have to do with selection, the selection can be done I'm 8C6 ways

Generally, nCr = n!/(n-r)!r!

8C6 = 8!/(8-6)!6!

= 8!/2!6!

= 8×7 × 6!/2!6!

= 8×7/2!

= 56/2

= 28ways

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3 years ago
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You flipped a coin 50 times and got 23 heads.What is the experimental probability of getting a head? Write your answer as a frac
lys-0071 [83]

Answer:

23/50, 0.46, and 46%

Step-by-step explanation:


This problem is stating that every fifty times you flip a coin you get 23 heads. Finding the fraction is simple, it would be 23/50 because it is expressing the probability. The problem clearly states that every 50 times you get 23 heads. To find the decimal, take the fraction, 23/50, and multiply the numerator and denominator by 2. you get 46/100 which is 0.46. A percent is just a fraction out of a 100 which would make the percent 46.


8 0
3 years ago
Make sure you draw a picture to help solve the problem and show all your work:
hodyreva [135]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. Find the probability that t
icang [17]

Answer:

The probability that the first card is a Heart and the second card is a Spade is 0.064.

Step-by-step explanation:

A standard deck of 52 cards is shuffled and two cards are drawn without replacement.

The denominations of the cards are as follows:

Spades (S) = 13

Hearts (H) = 13

Diamonds (D) = 13

Clubs (C) = 13

Compute the probability of selecting a Heart first as follows:

P(H)=\frac{13}{52}=0.25

Compute the probability of selecting a Spade second as follows:

P(S)=\frac{13}{51}=0.255

Since the two cards are selected without replacement the second draw is independent of the other.

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P(1st\  H\cap 2nd\ S)=P(H)\times P(S)

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Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.

4 0
3 years ago
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